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sveticcg [70]
3 years ago
7

Four friends played minutes golf. Their scores were -3, -2, -1, and 2.

Mathematics
1 answer:
kramer3 years ago
6 0
I had the same question just yesterday and the correct answer was 1.5 
-3 +-2 = -5 + -1 = -6 - 2 = -4

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I need help please! I will mark you as a brainlest and give out 30 points!
klio [65]
Answer:
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Step-by-step explanation:
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3 0
2 years ago
Use vieta's theorem to solve the problems.
Mnenie [13.5K]

Using Vieta's Theorem, it is found that c = 72.

<h3>What is the Vieta Theorem?</h3>
  • Suppose we have a quadratic equation, in the following format:

y = ax^2 + bx + c

  • The roots are p and q.

The Theorem states that:

p + q = -\frac{b}{a}

pq = \frac{c}{a}

In this problem, the polynomial is:

x^2 - 17x + c

Hence the coefficients are a = 1, b = -17.

Since the difference of the solutions is 1, we have that:

p - q = 1

p = 1 + q

Then, from the first equation of the Theorem:

p + q = -\frac{b}{a}

1 + q + q = 17

2q = 16

q = 8

p = 1 + q = 9

Now, from the second equation:

pq = \frac{c}{a}

72 = c

c = 72

To learn more about Vieta's Theorem, you can take a look at brainly.com/question/23509978

6 0
2 years ago
If I have 11 hours to do three things, how much time do I have to do each thing?
kogti [31]
11 hours = 3
1 = 3 hours 40 minutes
5 0
3 years ago
Read 2 more answers
Pi = 3.14
mr Goodwill [35]
Area of circle= 3.14r^2
r= 4
A= 50.27
8 0
3 years ago
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl
riadik2000 [5.3K]

Elimination Method

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}

If we multiply the equation 3 by (-1) we obtain this:

\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\  \end{gathered}

2. We can replace this value of X in the 1st and 2nd equations

\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}

3. If we simplify:

\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}

4. We can obtain Y from this two equations:

\begin{gathered} Y=-\frac{-12Z+58}{9} \\  \end{gathered}

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}

6. If we simplify, we obtain:

X=\frac{-3Z+7}{9}

7. In conclusion, we obtain that

(X,Y,Z) =

(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)

8 0
1 year ago
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