Answer:
the area is six units squared
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
9 x 2 = 18
6 x 3 = 18
and 18 x 1 = 18
Something percent of a number must be smaller than the number.
And also, 39% of a number is equal to 39/100 multiplied by the number.
Thus:
39/100 * 1200
39/1 * 12
468
The answer is -6.825 in fraction form, it would be -6 33/40
