Question

an object moves at a constant rate along a circular path with a radius 10 inches and makes 3 revolutions in 2 seconds.What is the linear velocity,in inches per second,of a point on the edge of the wheel

Answer 1

given:

radius= 10 inches

3 revolutions in 2 seconds.

to find:

the linear velocity.

solution:

$2\pi \: r = 2 \times \pi \times 10$

$= 62.85inches$

$(3 \times 62.85)$

$= 188.57$

$\frac{188.87}{2}$

$= 94.28$

hence, the linear velocity of the object is 94.28 in/s.

Answer 2

$\huge\bold\red{A}\purple{n}\pink{s}\orange{w}\blue{e}\green{r}$

Formula :

$\sf{2×π ×r }$

So,

$\sf{2×π× r }$

$\sf{2 × π × 10 × 2 }$

$\sf{62.8}$

~~~~~~~~~~~~~~

$\sf{3 × 62.8 }$

$\sf{188.4}$

~~~~~~~~~~~~~~

$\sf{\frac{188.4}{2}}$

$\sf{94.2}$