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Gwar [14]
3 years ago
12

True or false: f(x) is a function

Mathematics
2 answers:
Anna71 [15]3 years ago
8 0

Answer:

False

Step-by-step explanation:

If f(x) is a function , then for each value of x  there should be  a single y values

For input 0 there is a output 0

for input 10, the output is 2

for input 15, output is 3

For input 5, we have two output 1 and 3

for single input 5, the function cannot have two outputs 1  and 3

So this f(x) is not a function


stiv31 [10]3 years ago
5 0
False, since x values cannot have more than one y value.
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Can someone please help me
umka2103 [35]

Answer:

28/43

Step-by-step explanation:

The question asks what is the probability that Marley picks out a blue or yellow marble.

In total, there are 43 marbles.

In total, there are 28 blue and yellow marbles. (18+10=28)

So, the answer would be 28/43

Hope this helps

6 0
3 years ago
A paper company needs to ship paper to a large printing business. The paper will be
slamgirl [31]
45x+75y=1410 i hope this helps bc i’m pretty sure i’m learning the same thing but i hope this helps
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3 years ago
How many 4 digit codes are possible if the first digit cannot be 0 and digits can be repeated?
bezimeni [28]

Answer: 9,000

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4 0
3 years ago
Four randomly chosen Nevada students were asked how many times they drove to Arizona last year. Their replies were 4,5,6,7. The
den301095 [7]

The geometric mean of the numbers is 5.38

Given the values a, b, c and d

Geometric mean of the values will be expressed as:

GM = (abcd)^1/4

Given the values 4, 5, 6 and 7, the geometric mean will be expressed as:

GM = (4×5×6×7)^1/4

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Learn more: brainly.com/question/23875011

8 0
3 years ago
Calculate A^2, given A=[tex]Given A=[−3 4/-2 0}
MatroZZZ [7]

Answer:

\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }

Step-by-step explanation:

A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]

8 0
3 years ago
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