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adelina 88 [10]
1 year ago
6

In this problem you will compare the effects of different compounding periods on the interest an investment earns. Complete the

table below using the values indicated. Show the formula you used, with the correct values, in the second column. In the third column, give the result, rounded to the nearest cent.
Principal: $1,000
APR: 4.5%
Time: 10 years

Find the equations for annually, quarterly, monthly and daily
Mathematics
1 answer:
oee [108]1 year ago
3 0

Answer:

  see attached

Step-by-step explanation:

You are asked to use the compound interest formula for different values of n, the number of times per year the interest is compounded.

__

The basic formula is ...

  A = P(1 +r/n)^(nt)

for the amount in an account in which principal P earns interest at annual rate r compounded n times per year for t years.

The problem statement gives values for P, r, t, so we only need to compute the result for different values of n. With the given values filled in, the formula is ...

  A = 1000(1 +0.045/n)^(10n)

Values of n to be used are ...

  • annually: n = 1
  • quarterly: n = 4
  • monthly: n = 12
  • daily: n = 365

The formula you will evaluate uses these values where 'n' is in the formula. Corresponding account balances are ...

  • annual compounding: $1552.97
  • quarterly compounding: $1564.38
  • monthly compounding: $1566.99
  • daily compounding: 1568.27

__

For repetitive evaluation of the same formula, we like a calculator or spreadsheet. Many calculators have the "time value of money" formulas pre-programmed. This is shown in the second attachment, where the value that varies is "C/Y", the number of compoundings per year.

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Write an equation in slope - intercept form for the line that satisfies each set of conditions
ivanzaharov [21]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

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(1)

Rearrange 3x + 2y = 1 into this form by subtracting 3x from both sides

2y = - 3x + 1 ( divide all terms by 2 )

y = - \frac{3}{2} x + \frac{1}{2} ← in slope- intercept form

with slope m = - \frac{3}{2}

Parallel lines have equal slopes, thus

y = - \frac{3}{2} x + c ← is the partial equation

To find c substitute (- 6, 15) into the partial equation

15 = 9 + c ⇒ c = 15 - 9 = 6

y = - \frac{3}{2} x + 6 ← equation of line

(2)

Rearrange x + 2y = 8 into slope- intercept form by subtracting x from both sides

2y = - x + 8 ( divide all terms by 2 )

y = - \frac{1}{2} x + 4 ← in slope- intercept form

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Given a line with slope m then the slope of a line perpendicular to it is

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3 0
2 years ago
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HELP WITH THESE 3 QUESTIONS (BRIANLIEST AND 50 POINTS) hint: question 1 is answered (NO LINKS)
Rasek [7]

Answer:

45 points in round 3

Step-by-step explanation:

x + 30 + 25 = 100

combine like terms

30+25 = 55

x + 55 = 100

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Answer:

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Step-by-step explanation:

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3 years ago
What is the slope of the line that contains the point (13,-2) and (3,-2)
ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

<em><u>Solution:</u></em>

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

<em><u>Substituting the values in formula, we get,</u></em>

m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0

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