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adelina 88 [10]
2 years ago
6

In this problem you will compare the effects of different compounding periods on the interest an investment earns. Complete the

table below using the values indicated. Show the formula you used, with the correct values, in the second column. In the third column, give the result, rounded to the nearest cent.
Principal: $1,000
APR: 4.5%
Time: 10 years

Find the equations for annually, quarterly, monthly and daily
Mathematics
1 answer:
oee [108]2 years ago
3 0

Answer:

  see attached

Step-by-step explanation:

You are asked to use the compound interest formula for different values of n, the number of times per year the interest is compounded.

__

The basic formula is ...

  A = P(1 +r/n)^(nt)

for the amount in an account in which principal P earns interest at annual rate r compounded n times per year for t years.

The problem statement gives values for P, r, t, so we only need to compute the result for different values of n. With the given values filled in, the formula is ...

  A = 1000(1 +0.045/n)^(10n)

Values of n to be used are ...

  • annually: n = 1
  • quarterly: n = 4
  • monthly: n = 12
  • daily: n = 365

The formula you will evaluate uses these values where 'n' is in the formula. Corresponding account balances are ...

  • annual compounding: $1552.97
  • quarterly compounding: $1564.38
  • monthly compounding: $1566.99
  • daily compounding: 1568.27

__

For repetitive evaluation of the same formula, we like a calculator or spreadsheet. Many calculators have the "time value of money" formulas pre-programmed. This is shown in the second attachment, where the value that varies is "C/Y", the number of compoundings per year.

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Nadia is investigating rotations about the center of regular polygons that carry the regular polygon onto itself. She claims tha
GalinKa [24]

Answer:

\theta_1 \ n\ \theta_2 = 120, 240

Step-by-step explanation:

The question is incomplete, as the angles of rotation are not stated.

However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself

We have:

Nonagon = 9\ sides

Hexagon = 6\ sides

Divide 360 degrees by the number of sides in each angle, then find the multiples.

<u>Nonagon</u>

\theta = \frac{360}{9} =40

List the multiples of 40

\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320

<u>Hexagon</u>

\theta = \frac{360}{6} =60

List the multiples of 60

\theta_2 = 60, 120, 180, 240, 300

List out the common angles

\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320

\theta_2 = 60, 120, 180, 240, 300

\theta_1 \ n\ \theta_2 = 120, 240

This means that, only a rotation of 120, 240 will lift both shapes onto themselves, when applied to both shapes.

The other angles will only work on one of the shapes, but not both at the same time.

7 0
3 years ago
Can someone help me with this real quick?​
valentina_108 [34]

Answer:

11. A) 6x = 13

Step-by-step explanation:

11. Subtract 10 from both sides to make it equal 6x=13

12. For #12... None of the answers seem right? If you distribute and subtract, it should be

-4x + 44 = 66 then

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6 0
3 years ago
The number of miles Melody rides her bicycle, m, varies directly with the amount of time spent riding the bike, t. When Melody b
Minchanka [31]


the answer is A. m=7t     You get your answer by dividing 7 into m

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8 0
3 years ago
Read 2 more answers
Solve the equation. Then check your solution.
s344n2d4d5 [400]

Step-by-step explanation:

1.6a= -9.12

a= -9.12/1.6

=−5.7

option B

7 0
3 years ago
A rental car company charges $35 a day plus $.15/mi for a mid-size car. A customer owes $117.25 for a three-day rental. How many
Molodets [167]
The base charge is 35 dollars per day. He rented the car for 3 days, so before you add in the mileage you have to multiply 35 x 3 days for 105 dollars. Then you have to take the remaining charge and divide it by the charge per mile to get the number of miles driven.  Lets set up the equation.

d= number of days rented
m= number of miles driven

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105 + .15m = 117.25
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.15m = 12.25
m = 12.25/.15
m = 81.67

So he drove 81.67 miles
8 0
3 years ago
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