In this problem you will compare the effects of different compounding periods on the interest an investment earns. Complete the
1 answer:
Answer:
see attached
Step-by-step explanation:
You are asked to use the compound interest formula for different values of n, the number of times per year the interest is compounded.
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The basic formula is ...
A = P(1 +r/n)^(nt)
for the amount in an account in which principal P earns interest at annual rate r compounded n times per year for t years.
The problem statement gives values for P, r, t, so we only need to compute the result for different values of n. With the given values filled in, the formula is ...
A = 1000(1 +0.045/n)^(10n)
Values of n to be used are ...
- annually: n = 1
- quarterly: n = 4
- monthly: n = 12
- daily: n = 365
The formula you will evaluate uses these values where 'n' is in the formula. Corresponding account balances are ...
- annual compounding: $1552.97
- quarterly compounding: $1564.38
- monthly compounding: $1566.99
- daily compounding: 1568.27
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For repetitive evaluation of the same formula, we like a calculator or spreadsheet. Many calculators have the "time value of money" formulas pre-programmed. This is shown in the second attachment, where the value that varies is "C/Y", the number of compoundings per year.
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Answer:
Cuando María afirma que si unen sus dos cuartos de cartulina obtendrán el medio pliego que necesitan, esto es:
- <u>Verdadero</u>.
Step-by-step explanation:
Para entender mejor el ejercicio vamos a utilizar números cada vez que se habla de cantidades de cartulina, por lo tanto, María y Juan tienen 1/4 de cartulina cada uno, es decir, 1/4 * 2, y necesitan 1/2 pliego para poder realizar su tarea, por lo tanto, con la afirmación de María sobre unir los dos cuartos de cartulina, en caso de que sea verdadero, ocurrirá que la suma de los dos cuartos dará el medio pliego, como se muestra a continuación:
- Total de cartulina de María y Juan =
- Total de cartulina de María y Juan =
- Total de cartulina de María y Juan =
Procedemos a simplificar el fraccionario obtenido, sacando mitad tanto en el numerador como en el denominador:
- Total de cartulina de María y Juan =
- Total de cartulina de María y Juan =
- <u><em>Total de cartulina de María y Juan = </em></u>
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Como puedes ver al final, <u>la cantidad de cartulina de ambos, al ser sumada, da como resultado el 1/2 (medio) pliego que necesitan para su tarea de sociales, por lo cual la afirmación de María es correcta</u>.
Answer:
y = - 400 + 700x
Step-by-step explanation:
Nour's altitude increased at a constant rate from the Dead Sea up to Amman.
Initially, her altitude was 400 meters below from the sea level and then she arrived at an altitude was 1000 meters above sea level arrived to Amman, 2 hours later.
So, she moves (400 + 1000) = 1400 meters in 2 hours.
Therefore, her rate of change of altitude is meters per hour.
Therefore, if y represents Nour's altitude in meters relative to the sea level after x hours then the relationship between the altitude and number of hours is given by
y = - 400 + 700x (Answer)