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Savatey [412]
3 years ago
8

||BRAINLIEST||Drag the expressions to order them top to bottom from greatest to least.

Mathematics
2 answers:
Mademuasel [1]3 years ago
5 0

<em>Answer:</em>

<em>1. -10 8/9</em>

<em>2. 10 7/9</em>

<em>3. -10 5/9</em>

<em>4. -10 4/9</em>

<em>5. -9 8/9</em>

<em />

<em></em>

<em>Explanation:</em>

<em>I took the test on k12 and these were my answers, also pls rate and thank!:)</em>

<em />

<em>Hope this helped!:)</em>

devlian [24]3 years ago
3 0

Answer:

10 7/9

-9 8/9

-10 4/9

-10 5/9

-10 8/9

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X+6=6+x is it a one solution, infinite solutions or no solutions
Nookie1986 [14]

Answer:

infinite solutions

Step-by-step explanation:

6 0
3 years ago
Order the decimals 0.7 0.27 0.43 from least to greatest. Do the same thing with 0.4 0.22 0.72 what are your answers?
igor_vitrenko [27]

Answer:

0.27, 0.42, 0.7 & 0.22, 0.4, 0.72

Step-by-step explanation:

decimals 0.7 0.27 0.43 from least to greatest. Do the same thing with 0.4 0.22 0.72 what are your answers?

Arranging in ascending order ( 0.7,0.27,0.42) would be 0.27, 0.42, 0.7

This is gotten If all these decimals are converted to fractions with their denominator being 100 that is 27/100, 42/100, 70/100

Arranging in ascending order(0.4,0.22,0.72) would be 0.22, 0.4, 0.72

This is gotten If all these decimals are converted to fractions with their denominator being 100 that is 22/100, 40/100, 72/100

I hope this was helpful, please mark as brainliest

3 0
3 years ago
If P(x)=x^2-1 and q(x)=5(x-1), which expression is equivalent to (p-q)(x)
soldier1979 [14.2K]
All you need to do p(x)-q(x).  So:

(x^{2}-1)-(5)(x-1)

That's it!


3 0
3 years ago
Read 2 more answers
Can someone please help me thanks :)
Dmitrij [34]
29 degrees. You can just add 12 and 17 to find this, since the 12 is negative
7 0
3 years ago
Which statement about the best estimation strategy for this problem is correct? The Jackson family drove 490 miles each day for
dalvyx [7]
The answer is 4,172
First of all i did 490x9=2880
Then i did 2880+1292=4172
4172
6 0
4 years ago
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