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2 years ago

I need help, please!

Mathematics

1 answer:

nadya68 [22]2 years ago

6 0

Answer:

100

Step-by-step explanation:

$10^1=10\\\\10^2 = 100\\\\10^3 = 1000\\\\10^4 = 10000\\\\10^5 = 100000\\\\10^6 = 1000000$

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Identify the location of the point (-3, -2). A. P B. Q C. R D. S

docker41 [41]

Answer:

You haven't given a picture of the graph dear.

The point (-3,-2) lies in the third quadrant.

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3 years ago

Here are four false statements about the graph.

frosja888 [35]

Answer:

Range:y $\leq$ 5

Step-by-step explanation:

Since y is always less than 5, y cannot be equal to it since the highest value of y was about 4.

4 0

4 years ago

Hi I need help lol

yKpoI14uk [10]

Answer: 105 degrees

Step-by-step explanation:

so, since it is a parallelogram, adjacent angles are equal. so, we know that angle S and angle U are equal. that means we can subtract 150 from the 360 degrees of the full parallelogram. so, that leaves 210 degrees to work with. since it is shared amongst the other two equal angles, we just divide it by 2. so, that's how we get the answer.

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3 years ago

Let f(x)=9x-1 and g(x)=x^3. Evaluate (f*g)(-1)

ale4655 [162]

The answer is 10 (:

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8 0

3 years ago

In engineering, the modulus of elasticity is a way to measure how much an object deforms along an axis when opposing forces are

Allushta [10]

Step-by-step explanation:

Consider an engineering material of initial length Lo, Area (A), Modulus of elasticity (E) and applied a force P due to which change in the length of the material is δ2 from it’s original length (Lo)

Initial length of the material is Lo. Hence, at time t = 0 when no force applied on the material the length of the material will not change (i.e., at time t=0, δ1 = 0)

Modulus of elasticity of the material:

$E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}$

Area of the material:

$E=\frac{P \cdot L_{o}}{A\left[\delta_{2}-\delta_{1}\right]}$

$A=\frac{P \cdot L_{o}}{E\left[\delta_{2}-\delta_{1}\right]}$

Length of the material:

$E=\frac{P \cdot L_{0}}{A\left[\delta_{2}-\delta_{1}\right]}$

$L_{0}=\frac{E \cdot A\left[\delta_{2}-\delta_{1}\right]}{P}$

5 0

3 years ago