Answer:
<h3>Q1</h3>
The graph of y = f(x), has vertex at (1, -2)
<u>The vertex of a function f(x - 3) is going to be:</u>
<h3>Q2</h3>
- <em>The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).</em>
The axis of symmetry is at the same distance from the symmetric points.
x = 5 is a vertical line. The point (8, -7) is 3 units to the right. So the mirror point will be 3 units to the left and have same y-coordinate: x = 5 - 3 = 2
The point is (2, -7)
<h3>Q3</h3>
The graph in blue is the translation of the red to the left by 2 units.
<u>So the equation is:</u>
<h3>Q4</h3>
y = h(x) is graphed
- h(7) = 5
- h(h(7)) = h(5) = -1
<h3>Q5</h3>
The graph of the function y = u(x) given
This is a odd function.
The coordinates of u(x) and u(-x) add to zero because u(-x) = -u(x)
<u>Therefore:</u>
- u(-2.72) + u(-0.81) + u(0.81) + u(2.72) =
- [u(-2.72) + u(2.72)] + [u(-0.81) + u(0.81)] =
- 0 + 0 = 0
Answer:
61
Step-by-step explanation:
4 × (8 + 5) + 9
Parentheses first
4 × (13) + 9
Then multiply
52 +9
Then add
61
U will have some left but idn sry but give me a like for trying :p
If it is shaded 1/5 color only 1
Answer:
66) P = 38m
67) P = 32.7m
Step-by-step explanation:
Perimeter of triangle
P = a + b + c
P = 8 + 16 + 14
P = 38m
Perimeter of trapezoid
P = a + b + c + d
P = 6.4 + 13.6 + 6 + 6.7
P = 32.7
