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3 years ago

What statement statement is not true is not true

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

5 0

C is the answer because with this kind of math the answer can be Neg or Postive

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Help plsssssss homewrok do taday -2x - 3y = 6

OlgaM077 [116]

Answer:

x=0/y=-2

y=0/x=-3

....∞

Step-by-step explanation:

6 0

3 years ago

HELP ME PLZ PLZ PLZ!

Triss [41]

Answer:

I don't know the value of either, could you add more information?

Step-by-step explanation:

I'd be glad to help.

6 0

3 years ago

Tomika uses 6/19 inches of wire to make a necklace and 3/13 inches of wire to make a bracelet.

Kay [80]

Answer:

#Answer: 3 Step-by-step explanation: Common sence 8 months ago 3 0 Answer: There are 3 necklace and bracelet sets she can make . Step-by-step explanation: Since we have given that Length of wire she used to make a necklace is given by Length of wire she used to make a bracelet is given by Total length of wire she is used in all is given by Now, we calculate number of necklace and bracelet sets she can make , So, So, there are 3 necklace

7 0

3 years ago

Please help i dont know how to do this

maxonik [38]

Hello once again!

When you see a question like this, you need to find the equation of the straight line.

The formular used is y = mx + c
Where
m = slope
c = constant

First find the slope, since it's a straight line, any 2 coordinates can be used.

$m = { \frac{y_1 - y_2}{x_1-x_2} } \\ m= { \frac{16 - (- 8)}{-2 - 2} } \\ m= { \frac{24}{-4} } \\ m = -6$

Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.

In this case i'm using the coordinate
(-2, 16)

y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4

∴ The equation of the line is y = -6x + 4

The next step is to simply substitude in the x = 8 to the equation to find y.

y = -6(8) + 4
y = -48 + 4
y = -44

7 0

3 years ago

4 Tan A/1-Tan^4=Tan2A + Sin2A

Eva8 [605]

tan(2A) + sin(2A) = sin(2A)/cos(2A) + sin(2A)

• rewrite tan = sin/cos

… = 1/cos(2A) (sin(2A) + sin(2A) cos(2A))

• expand the functions of 2A using the double angle identities

… = 2/(2 cos²(A) - 1) (sin(A) cos(A) + sin(A) cos(A) (cos²(A) - sin²(A)))

• factor out sin(A) cos(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (1 + cos²(A) - sin²(A))

• simplify the last factor using the Pythagorean identity, 1 - sin²(A) = cos²(A)

… = 2 sin(A) cos(A)/(2 cos²(A) - 1) (2 cos²(A))

• rearrange terms in the product

… = 2 sin(A) cos(A) (2 cos²(A))/(2 cos²(A) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(A)

… = 4 sin(A) cos(A) / (2 - 1/cos²(A))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(A) cos(A) / (2 - sec²(A))

• divide through again by cos²(A)

… = (4 sin(A)/cos(A)) / (2/cos²(A) - sec²(A)/cos²(A))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(A) / (2 sec²(A) - sec⁴(A))

• factor out sec²(A) in the denominator

… = 4 tan(A) / (sec²(A) (2 - sec²(A)))

• rewrite using the Pythagorean identity, sec²(A) = 1 + tan²(A)

… = 4 tan(A) / ((1 + tan²(A)) (2 - (1 + tan²(A))))

• simplify

… = 4 tan(A) / ((1 + tan²(A)) (1 - tan²(A)))

• condense the denominator as the difference of squares

… = 4 tan(A) / (1 - tan⁴(A))

(Note that some of these steps are optional or can be done simultaneously)

7 0

3 years ago