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Alinara [238K]
2 years ago
5

15 days ago, the share of the Valmont family business was worth $156. Over the next 5 days, the stock value increased by $3 per

day. Then its value went down by $5 a day for 10 days.
What is the value of the stock today?

Using Order of Operation
please answer i need it today :'(​
Mathematics
1 answer:
MAVERICK [17]2 years ago
5 0

Answer:

compute the company's price-to-earnings (P/E) ratio.

Step-by-step explanation:

When companies issue additional shares, it increases the number of common stock being traded in the stock market. For existing investors,

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What is the fraction of 2.5
tekilochka [14]
We are looking for the fraction form or 2.5.

2.5 = 2 5/10 = 2 1/2

It would be 2 1/2 or 5/2. Hope this helps!
4 0
4 years ago
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Determine the area of the rhombus base 6 height 4
Leno4ka [110]
48
There are two sets of equal triangles together they each equal a square so one sets area is 36 and the others area is 12
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3 years ago
How do u solve 2/8=4
timofeeve [1]

Answer:

8/8 (then entire number) is 16

Step-by-step explanation:

4/2 = 2

2x8=16

so 8/8=16

8 0
3 years ago
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a gold mine extracted 500,000 ounces. gold is priced at present time at $460 per ounce. the mine holds gold for 3 years. if infl
tresset_1 [31]

Answer:

<h2>$267,536,000</h2>

Step-by-step explanation:

Step one:

given data

total ounces=500,000

cost per ounce= $460

total amount of the ounce= 500,000*460= $230000000

Time t=3years

rate= 5.17%= 0.0517

Step two:

The inflation we have a compounding effect on the amount

$230000000

A=P(1+r)^t

A=230000000(1+0.0517)^3

A=230000000(1.0517)^3

A=230000000*1.1632

A=$267,536,000

<u>They will receive a total of  $267,536,000</u>

4 0
3 years ago
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.64 years and the standard deviation i
____ [38]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

Assuming that conditions have been met for the interval, we use the formula \displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}} where \bar{x} represents the sample mean, t represents the critical value, s represents the sample standard deviation, and n is the sample size.

The critical value of t for an 80% confidence level with degrees of freedom df=n-1=25-1=24 is equivalent to t=1.317836

Thus, we can compute the confidence interval:

\displaystyle CI=\bar{x}\pm t\frac{s}{\sqrt{n}}\\\\CI=32.64\pm1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\\\\CI\approx\{30.17,35.11\}

Therefore, we are 80% confident that the true mean age of all customers is between 30.17 and 35.11 years.

<u>Part B</u>

The margin of error is \displaystyle t\frac{s}{\sqrt{n}}=1.317836\biggr(\frac{9.39}{\sqrt{25}}\biggr)\approx2.47

6 0
2 years ago
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