To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
The answer to this will be,
c. It will terminate.
Answer:
i believe the other side is the 50 or 60 in length
Step-by-step explanation:
You multiply 86 x .45 and you get the answer of 38.7
(88sin20)(t - 16t²) = 0
(8(0.3090169944)(t - 16t²) = 0
(2.472135955)(t - 16t²) = 0
2.472135955t - 39.55417528t² = 0
