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nataly862011 [7]
3 years ago
12

The function h(t) = -4.922 +17.694+ 575 is used to model the height of an object being tossed from a tall building, where

Mathematics
1 answer:
wel3 years ago
5 0

Correct question is;

The function h(t) = -4.92t ² + 17.69t + 575 is used to model an object being tossed from a tall building, where h(t) is the height in meters and t is the time in seconds. Rounded to the nearest hundredth, what are the domain and range?

Answer:

The domain and range are:

Domain: [0, 12.76]

Range: [0, 590.9]

Step-by-step explanation:

For the domain;

Let's find the root of the given function h(t) = -4.92t ² + 17.69t + 575.

We will do it by Equating h(t) to zero and using quadratic formula;

So;

-4.92t ² + 17.69t + 575 = 0

t = [-17.69 ± √(17.69² - 4(-4.92 × 575))]/(2 × -4.92)

Solving with a calculator, the roots are

t = -9.16 or t = 12.76

We ignore the negative root and make use of the positive root.

Thus, the domain is:

[0, 12.76]

For the range:

Let's find the derivative of the given function:

Thus;

h'(t) = -9.84t + 17.69

Again like we did for the domain, we will equate to zero to find t

Thus;

-9.84t + 17.69 = 0

t = 17.69/9.84

t ≈ 1.8

Thus, this is the time at which the object being tossed reaches the maximum height of the function.. Thus max height at t = 1.8 is;

h(1.8) = (-4.92 × 1.8²) + (17.69 × 1.8) + 575

h(1.8) = -15.9408 + 31.842 + 575

h (1.80) ≈ 590.9

So the range is; [0, 590.9]

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5 0
2 years ago
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Priscilla can make 4 bracelets in 13 minutes. At this rate, how many bracelets can she make in 26 minutes?
Degger [83]

Answer:

8

Step-by-step explanation:

To find the answer, multiply 4 and 2 together, since 13 is 2 times less than 26.

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Let's double check,

26 ÷ 13 = 2

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Have a good day :)

4 0
3 years ago
X =x=x, equals <br> ^\circ <br> ∘
kolbaska11 [484]

Answer:

here,

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3 0
1 year ago
Andrew claims the initial value and y - intercept are the same thing on a graph. Is he correct?
Agata [3.3K]

Answer:

We conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

Step-by-step explanation:

We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.

In other words, the initial value is the y-value or output of the point at x = 0

For example,

Let the equation

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substitute x = 0

y = 2(0)+1

y = 0+1

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Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Thus, at y = 1, the line meets the y-axis.

Hence, the initial value of the line is: y = 1

Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the y-intercept of y = 2x+1 is y = 1.

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

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Conclusion:

Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

6 0
2 years ago
What is the value of d? Assume that the line is a tangent to the circle.
motikmotik

We have been given a chord and tangent to a circle. We have been minor arc measure that is equal to 118^{0}.

Since we know that angle formed by a secant and tangent of circle is half of the measure of intercepted arc.

\measuredangle x=\frac{1}{2}m \widehat{ABC}

We can find intercepted arc by subtracting minor arc measure from 360 degrees because minor and major arcs add up to 360 degrees.

360^{0}-118^{0}=242^{0}

Now we will plug given values in our  formula,

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5 0
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