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kirill115 [55]
2 years ago
13

I. GIVEN TRIANGLE POR, DETERMINE THE FOLLOWING. please help me out with this ​

Mathematics
2 answers:
STALIN [3.7K]2 years ago
8 0

This is a lengthy question ill go through all the formulas

This is a right triangle which means u can use pythagorean theorem to find QP

formula :

a^{2} +b^{2} =c^{2}

Note that c^{2} is always the hypotenuse(the hyp is always opposite to ninety degrees)

so lets substitute

=> a^{2} +17^{2} =28^{2}

=> a^{2} +289 =784

subtract 289 both sides

= > a^{2}=495

Now square root both

\sqrt{ a}^{2}=\sqrt{495}

==> 3\sqrt{55} or 22.2 (answer)

But for the other three u have to use another formula any of sin, tan,cos while using For example angle Q and then use any and do inverse it will be very easy after u know all the formulas of Sin,cos, tan

SOHCAHTOA

^

Thats an acronym   for the formula

Sin= Opposite/ hyp

Cos= Adjustent/Hyp

Tan= Opposite/Adjustent

Digiron [165]2 years ago
7 0

34

Step-by-step explanation:

 122

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