Question

I. GIVEN TRIANGLE POR, DETERMINE THE FOLLOWING. please help me out with this ​

Answer 1

This is a lengthy question ill go through all the formulas

This is a right triangle which means u can use pythagorean theorem to find QP

formula :

$a^{2} +b^{2} =c^{2}$

Note that $c^{2}$ is always the hypotenuse(the hyp is always opposite to ninety degrees)

so lets substitute

=> $a^{2} +17^{2} =28^{2}$

=> $a^{2} +289 =784$

subtract 289 both sides

$= > a^{2}=495$

Now square root both

$\sqrt{ a}^{2}=\sqrt{495}$

==> $3\sqrt{55}$ or 22.2 (answer)

But for the other three u have to use another formula any of sin, tan,cos while using For example angle Q and then use any and do inverse it will be very easy after u know all the formulas of Sin,cos, tan

SOHCAHTOA

^

Thats an acronym   for the formula

Sin= Opposite/ hyp

Cos= Adjustent/Hyp

Tan= Opposite/Adjustent

Answer 2

34

Step-by-step explanation:

 122