Question

What is the solution of the system of equations c+3d=8 and c=4d-6? Show work plz.

Answer 1

$\left\{\begin{array}{ccc}c+3d=8\\c=4d-6\end{array}\right\\\\substitute:\\\\(4d-6)+3d=8\\4d+3d-6=8\ \ \ \ /+6\\7d=14\ \ \ \ /:7\\d=2\\\\c=4\cdot2-6=8-6=2\\\\\left\{\begin{array}{ccc}c=2\\d=2\end{array}\right$