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3 years ago

5

What is the slope of the line shown in the graph? A 3/2 B) 2/3 C) -3/4 D) -2/3

2 answers:

Alex777 [14]3 years ago

8 0

D. -2/3 because when you find when the line lies on 1 point twice. Count down it would be 2 and count over it would be 3. The direction of the line is going down so that would be negative.

garik1379 [7]3 years ago

6 0

Answer:

D.

Step-by-step explanation:

y-intercept is (0, 3)

x-intercept is (4.5, 0)

formula to find the slope from two points is

$slope = m = \frac{y2 - y1}{x2 - x1} = \frac{y1 - y2}{x1 - x2} \\$

then the slope of the line that crosses (0, 3) & (4.5, 0) is

$m = \frac{3 - 0}{0 - 4.5} = \frac{3}{ - 4.5} = - \frac{3}{ \frac{9}{2} } = - \frac{2}{3}$

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3 years ago

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

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Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

So

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

So

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

4 years ago