14,494
To round off the height value to the nearest thousand we can use the
expanded from to clarity the position of numbers which is:
10, 000 = ten thousand
4, 000 = thousands
400 = hundreds
90 = tens
4 = ones
Here we can notice than four thousand is the value where the nearest
thousands is placed. Hence we can round off the number of 14, 494 into 14, 000.
Notice 0-4 rounding off rules.
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer:
See explanation
Step-by-step explanation:
We want to show that:
One way is to use the basic double angle formula:
We simplify further to get:
We simplify again to get;
This finally gives:
Answer: the answer is E, 8000
Step-by-step explanation:
V=L×W×H
Answer:
multiply length with breadth which is 34 *42
