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3 years ago

What’s 12-1/3= as a fraction

Mathematics

2 answers:

aev [14]3 years ago

7 0

12 - 1/3

= 36/3 - 1/3

= 35/3.

jekas [21]3 years ago

3 0

It would be 20/3 or 6 2/3

Hope this helps

Have a great day/night

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Question 12.12. In 2010, the population of a city was 65,903. It was expected to grow at a rate of 0.7% each year.

postnew [5]

$y=Ce^{kx}$

k=0.7%=0.007

$65903=Ce^{.007(0)} \\ 65903=Ce^0 \\ 65903=C(1) \\ C = 65903$

$y=65903e^{0.007(2027-2010)}\\y=65903e^0.229 \\ y = 74231.157$

The best answer is 74,200

8 0

4 years ago

Can you please help!!!

Masja [62]

Answer:

ok ok! i got you! =D

300+60 +8 = 368 so 300+60+8 matches with the first box

3,000+600+80 = 3,680 so 3,000+600+80 matches with the second box

30,000+600+80= 30,680 so 30,000+600+80 matches with the third box

that's it!

have a good day!

6 0

3 years ago

What is the product of 8 and 54

tiny-mole [99]

The product of the two numbers is 432.

4 0

3 years ago

Read 2 more answers

Evaluate each of the integrals (here δ(t) is the dirac delta function) (1) ∫∞−∞e5tδ(t−2)dt= (2) ∫∞−∞cos(2t)δ(t−5)dt= (3) ∫∞0e−st

Viktor [21]

$\delta(x)$ has the property that for any continuous $f$ with support in $\mathbb R$ ,

$\displaystyle\int_{-\infty}^\infty f(x)\delta(x-c)\,\mathrm dx=f(c)$

where $c\in\mathbb R$ . So we have

$\displaystyle\int_{-\infty}^\infty e^{5t}\delta(t-2)\,\mathrm dt=e^{10}$

$\displaystyle\int_{-\infty}^\infty\cos2t\,\delta(t-5)\,\mathrm dt=\cos10$

The remaining two integrals are identical to the Laplace transforms of $\cos3t\,\delta(t-2)$ and $t^3\sin t\,\delta(t-3)$ . For these, we have the property that

$\mathcal L_s\{f(t)\delta(t-c)\}=f(c)e^{-sc}$

so we get

$\displaystyle\int_0^\infty e^{-st}\cos3t\,\delta(t-2)\,\mathrm dt=\mathcal L_s\{\cos3t\,\delta(t-2)\}=\cos6\,e^{-2s}$

$\displaystyle\int_0^\infty e^{-st}t^3\sin t\,\delta(t-3)\,\mathrm dt=\mathcal L_s\{t^3\sin t\,\delta(t-3)\}=27\sin3\,e^{-3s}$

8 0

3 years ago

What is the solution to the system of equations? 3x + 10y = -47 5x- 7y = 40<br>Please and thank u

anastassius [24]

Answer:

x=1, y=-5

Step-by-step explanation:

Given equations are:

$3x+10y=-47\ Eqn\ 1\\and\\5x-7y=40\ Eqn\ 2$

In order to solve the equation

Multiplying Eqn 1 by 5 and eqn 2 by 3 and subtracting them

So,

Eqn 1 becomes

15x+50y=-235

Eqn 2 becomes

15x-21y=120

Subtracting 2 from a

15x+50y - (15x-21y) = -235-120

15x+50y-15x + 21y = -355

71y = -355

y = -355/71

y =-5

Putting y= -5 in eqn 1

3x+10(-5) = -47

3x -50 = -47

3x = -47+50

3x = 3

x = 3/3

x = 1

Hence the solution is:

x=1, y=-5

5 0

3 years ago

Read 2 more answers