I am on my trigonometry unit in math and don’t know what to do for this. I also really need work shown!
1 answer:
Answer:
The flight was 137.45 miles farther than the direct path.
(make slight changes if directions were given on how to round. This is to the nearest hundredth)
Step-by-step explanation:
Use the Law of Cosines.
c^2=
a^2+b^2-2abcosC
You know two sides and the angle in between. The Law of Cosines will give us the third side.
The third side is the direct path of the airplane. We'll add the two other given sides to find the detour route that they took instead.
Then subtract the smaller number (direct route) from the actual route. See image.
You might be interested in
Answer:
a) 38"
b) L = 5.7'
Step-by-step explanation:
a) Given
P = 9,500 lb/ft
Thick = 18"
We assume an allowable bearing pressure of σ = 3000 lb/sf
If Stress = Force / Area
σ = P/A
Solving for area
A = P/σ ⇒ A = 9,500 lb/ft/3000 lb/sf
⇒ A = 3.167 sf, or 3.167 ft wide, per foot of length.
⇒ A = 38" wide
We can see the pic 1 in order to understand the answer.
b) Given
P = 65,000 pounds = 65,000 lb
Thick = 18" = 1.5'
We assume an allowable bearing pressure of σ = 2000 lb/sf
If Stress = Force / Area
σ = P/A
Solving for area
A = P/σ ⇒ A = 65,000 lb/2000 lb/sf
⇒ A = 32.5 sf
then A = L² ⇒ L = √A = √(32.5 sf) = 5.7 ft
Finally L = 5.7'
We can see the pic 2 in order to understand the answer.
