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2 years ago

7

Juliana bought 3 bags of chips for 0.85 each and 3 sodas for herself and two friends and spent exactly $6 (before tax.) write an

equation to find the price of each can of soda.

1 answer:

sineoko [7]2 years ago

7 0

Answer: Cost of 1 soda = (Amount Juliana had- Cost of 3chips)/3

Step-by-step explanation: Cost of 3chips =$0.85×3= $2.55

Cost of 3 soda will be $6-$2.55
Cost of 1soda will be ($6-$2.55)/3

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*30 POINTS* HELP FOR BRAINLIEST

Marta_Voda [28]

Answer:

21

Step-by-step explanation:

f(x) =x^2 - 6x + 21

f(xl =0

Answer:

substitute 0 for x

f(0) = 0^2 - 6(0) + 21

0. = 0 - 0 + 21

0. = 21

6 0

3 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$

So

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 16) = C_{20,16}.(0.75)^{16}.(0.25)^{4} = 0.1897$

$P(X = 17) = C_{20,17}.(0.75)^{17}.(0.25)^{3} = 0.1339$

$P(X = 18) = C_{20,18}.(0.75)^{18}.(0.25)^{2} = 0.0669$

$P(X = 19) = C_{20,19}.(0.75)^{19}.(0.25)^{1} = 0.0211$

$P(X = 20) = C_{20,20}.(0.75)^{20}.(0.25)^{0} = 0.0032$

So

$P(X \geq 16) = P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.1897 + 0.1339 + 0.0669 + 0.0211 + 0.0032 = 0.4148$

c. If you call 22 times, what is the mean number of calls that are answered in less than 30 seconds? Round your answer to the nearest integer.

The expected value of the binomial distribution is:

$E(X) = np$

In this question, we have $n = 22$

So

$E(X) = 22*0.75 = 16.5$

The closest integer to 16.5 is 17.

7 0

3 years ago

What is the skipping sequence of 90,92,__,__,99,__

DaniilM [7]

that is not possible cause the first 2 indicate that the pattern is counting by 2s

5 0

3 years ago

Help me on this please !

inna [77]

Answer:

24.08

Step-by-step explanation:

We use the Pythagorean theorem and we get (16)^2 + (18)^2 = (x)^2

256 + 324 = x^2

x^2 = 580

x is about 24.08.

7 0

3 years ago

Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 2,250,000 and a mean

Svet_ta [14]

Answer: 0.1357

Step-by-step explanation:

Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of $\sigma^2=2,250,000$ and a mean life span of $\mu=13,000$ hours.

Here , $\sigma=\sqrt{2250000}=1500$

Let x represents the life span of a monitor.

Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-

$P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357$

Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357

6 0

3 years ago