How to fing the area of trapizium

2 answers:

8 0

The area of a trapezium is computed with the following formula: Area = 1 2 × Sum of parallel sides × Distance between them .

aleksklad [387]2 years ago

6 0

Answer:

area = (1/2) · (p + q) · h

Step-by-step explanation:

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What is the answer and how do you solve <br><br><br> 21x^3/3x^−1

Sunny_sXe [5.5K]

Answer:

as written: 7x^2

perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^b/a^c = a^(b-c)

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2 years ago

Angle 1 and angle 2 are vertical angles. If m angle 1 = (8x+12)° and m angle 2 = (3x+37)° find the measure for each angle.

laila [671]

Vertically opposite angles are always equal.

Given angles are (8x+12)° and (3x+37)°

=> (8x+12)° = (3x + 37)°

=> 8x - 3x = 37-12

=> 5x = 25

=> x = 25/5 = 5°

Angle 1 = (8x+12)° = (8(5)+12) = 40+12 = 52°

Angle 2 = (3x + 37)° = (3(5)+37)° = 15+37 = 52°

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Ilya [14]

(-2,0) (0,6) (1,0) this should be it

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Which is a point on the circle whose center is (0, 0) and whose radius is 5?

Jet001 [13]

Answer:

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