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3 years ago

The circle has a radius of 3 cm. What is the area of the circle?

Mathematics

2 answers:

ohaa [14]3 years ago

8 0

Answer:

D: 28.26

Step-by-step explanation:

STatiana [176]3 years ago

6 0

You would do
3.14*r^2
which is 3
r=3
what you do is
3.14*3*3 which is 28.26cm^2 which is D

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WHAT IS THE DIFFERENCE BETWEEN RECURSIVE AND EXPLICIT FORMULAS FOR SEQUENCES AND SERIES'?

ElenaW [278]

Https://www.youtube.com/watch?v=JnCYomYzJSw
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3 years ago

The nutritional chart on the side of a box of a cereal states that there are 87 calories in a 3/4 cup serving. How many calories

alexira [117]

Answer:

Total calories in 8 cup = 928 calories

Step-by-step explanation:

Given:

Calories in 3/4 cup of cereal = 87 calories

Find:

Total calories in 8 cup

Computation:

Total calories in 8 cup = 8 x 87 x [4/3]

Total calories in 8 cup = 928 calories

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3 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

Graph the solutions of the inequality

Fiesta28 [93]

Answer:

The graph in the attached figure

Step-by-step explanation:

Graph the solution of the inequality

$t\leq -4$

we know that

The solution is the interval ---> (-∞,-4]

All real numbers less than or equal to -4

In a number line the solution is the shaded area at left of t=-4 (closed circle, because the number -4 is included in the solution))

using a graphing tool

The graph in the attached figure

6 0

3 years ago

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Paraphin [41]

The answer is 360.42 or 360

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3 years ago

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