Answer:0.0081 or 0.81%
Step-by-step explanation:
The required probability is P(3,5,0.1)= C5 3 * p^3*q^2, where
C5 3= 5!/3/2=4*5/2=10
p is the probability that one randomly selected calculator is defective= 10%=0.1
q is the probability that one randomly selected calculator is non-defective.
q=1-p=1-0.1=0.9
So P(3,5,0.1)= 10*0.1^3*0.9^2=0.01*0.81=0.0081
The answer to this probability question is .86 or 86%. The probability that a batch of 10,000 batteries will contain at least 175 defective batteries is 86 percent. I calculated the failure rate of 10,000 batteries (10k*.015) and yielded 150, meaning there will be 150 batteries that will be defective in a set of 10,000. Then i divided 150 by 175 to get the probability.
What? I don't understand what you mean...
Answer:
1st, 2nd, and last.
Step-by-step explanation:
For the first two common rules can be applied such as 
= ![\frac{\sqrt[n]{a} }{\sqrt[n]{b} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5Bn%5D%7Ba%7D%20%7D%7B%5Csqrt%5Bn%5D%7Bb%7D%20%7D)
and that ![\sqrt[n]{\frac{a}{b} } = (\frac{a}{b})^{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%3D%20%28%5Cfrac%7Ba%7D%7Bb%7D%29%5E%7Bn%7D)
and for the last one this is just simplifying the radical and if you factor it you realize that, 
meaning that you can take the radical off of 5/8 and end up with that final answer
0 because 0 times anything is 0
