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Anastasy [175]
2 years ago
8

Which function has an inverse that is also a function?

Mathematics
1 answer:
Vlad [161]2 years ago
6 0

keeping in mind that a function does not have any X-Repeats, that is, the 1st coordinate in every pair never repeats, well, in this case, all of them have no X-repeats, that means all of them are functions.  However, only one-to-one functions have an inverse that is also a function.

A one-to-one function is one that has no X-repeats as well as no Y-repeats, so each pair in the set has no coordinate repeats, Check the picture below.

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LUCKY_DIMON [66]

Answer:

c

Step-by-step explanation:

C. This is the correct answer because the wage rises by $2, which is 2/20=10% increase. Next year the increase percent is 2.20/22=10%. That's a constant percent increase

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If two segments are both parallel to a third line they must be:

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A line with slope -2 and y-intercept 4
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Answer:

y = -2x + 4

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If the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb, how much work is needed to stretch it 6 in.
mel-nik [20]

Answer:

0.375 feet-lb

Step-by-step explanation:

We have been given that the work required to stretch a spring 2 ft beyond its natural length is 6 ft-lb. We are asked to find the work needed to stretch the spring 6 in. beyond its natural length.

We can represent our given information as:

6=\int\limits^2_0 {F(x)} \, dx

We will use Hooke's Law to solve our given problem.

F(x)=kx

Substituting this value in our integral, we will get:

6=\int\limits^2_0 {kx} \, dx

Using power rule, we will get:

6=\left[ \frac{kx^2}{2} \right ]^2_0

6=\frac{k(2)^2}{2}-\frac{k(0)^2}{2}

6=\frac{4k}{2}-0\\\\k=3

We know that 6 inches is equal to 0.5 feet.

Work needed to stretch it beyond 6 inches beyond its natural length would be \int\limits^{0.5}_0 {kx} \, dx =\int\limits^{0.5}_0 {3x} \, dx

Using power rule, we will get:

\int\limits^{0.5}_0 {3x} \, dx = \left [\frac{3x^2}{2}\right]^{0.5}_0

\frac{3(0.5)^2}{2}-\frac{3(0)^2}{2}\Rightarrow \frac{3(0.25)}{2}-0=\frac{0.75}{2}=0.375

Therefore, 0.375 feet-lb work is needed to stretch it 6 in. beyond its natural length.

3 0
3 years ago
Round 38224 correct to 1 significant figure​
sattari [20]
The answer is 40000!
6 0
3 years ago
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