All categories

3 years ago

What numbers are a distance of 3 units from -6 on a number line

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

7 0

-6+3=-3
-6-3=-9
so -3 and -9

Mrrafil [7]3 years ago

5 0

Both -9 and -3 are three units from -6 on the number line

You might be interested in

I will give brainliest!!

harkovskaia [24]

Answer:

the area is 124.8 i believe because if you do 12 times 12 you get pretty much 124.8

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Circle O is shown. Secant A C intersects tangent C D at point C outside of the circle. Secant A C intersects circle O at point B

katrin [286]

Answer:

the answer is 194

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How is the surface area of a prism determined?

Oliga [24]

Answer:

Option b. sum of all areas of faces

Step-by-step explanation:

we know that

The surface area of the prism is equal to the area of its bases plus the area of its four rectangular lateral faces

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

therefore

sum of all areas of faces

7 0

3 years ago

Which expression below is equivalent to 2x + 8?

mash [69]

Answer: D) x+4+x+4

The two x terms combine to x+x = 2x

The other pair of like terms, the constants, add to 4+4 = 8

Overall we get 2x+8

2x+8 is also equivalent to 2(x+4) when you factor out the GCF 2.

7 0

3 years ago

Pleaaseeee help me :/

Sav [38]

Hello,

$\sqrt{x} - \sqrt{y} = (\sqrt[4]{x}+ \sqrt[4]{y} )( \sqrt[4]{x} - \sqrt[4]{y} )=72\\\\
\sqrt[4]{x}- \sqrt[4]{y}=6\\\\
(\sqrt[4]{x}+ \sqrt[4]{y})*6=72\\\\
\sqrt[4]{x}+ \sqrt[4]{y}=12 \\ 
\sqrt[4]{x}- \sqrt[4]{y}=6 \\\\
2 \sqrt[4]{x}=18==\textgreater\sqrt[4]{x}=9==\textgreater\ x=6561\\
2 \sqrt[4]{y}=6==\textgreater\sqrt[4]{y}=3==\textgreater\ y=81\\


$
Proof:
$\sqrt[4]{6561} - \sqrt[4]{81} =9-3=6\\\\
 \sqrt{6561} - \sqrt{81} =81-9=72$

8 0

3 years ago