Answer:
the correct answer is freedom
The limit from 1 to 2 of the given antiderivative is; -0.19865
<h3>What is the Limit of the Integral?</h3>
We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;

⇒ (sin ¹/₅) - (sin ¹/₂)
⇒ 0.19866 - 0.47942
⇒ -0.19865
Complete Question is;
If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?
Read more about integral limits at; brainly.com/question/10268976
Answer:
3 times
Explanation:
When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

Where:
Initial thickness,
= 2mm
Growth factor, r =8%=0.08
We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.
i.e When 

Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.
16.6666666666666666666666666666666666666666666666666666666666666666666666
B. Open admission. hope this helps