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rjkz [21]
1 year ago
6

My sis needs help asap

Mathematics
2 answers:
steposvetlana [31]1 year ago
7 0

Answer:

c. $750

Step-by-step explanation:

the perimeter is 80m

80÷8=10

10*75=750

nignag [31]1 year ago
4 0

Answer:The answer is b

Step-by-step explanation:

hope this helps.

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U and V are mutually exclusive events. P(U) = 0.27; P(V) = 0.56. Find:
Alisiya [41]

Answer:

(a) P (U and V) = 0.

(b) P (U|V) = 0.

(c) P (U or V) = 0.83.

Step-by-step explanation:

Mutually exclusive events are those events that cannot occur at the same time. That is, if events A and B are mutually exclusive then,

                                         P (A\cap B) = 0

<u>Given</u>:

Events U and V are mutually exclusive.

P (U) = 0.27 and P (V) = 0.56

(a)

As events U and V are mutually exclusive, the probability of their intersection will be 0.

That is,

P(U\ and\ V) = P (U\cap V) = 0

Thus, the value of P (U and V) is 0.

(b)

The conditional probability of event B given A is:

P(B|A) =\frac{P(A\cap B)}{P(B)}

Compute the value of P (U|V) as follows:

P(U|V) =\frac{P(U\cap V)}{P(V)}\\=\frac{0}{0.56}\\ =0

Thus, the value of P (U|V) is 0.

(c)

The probability of the union of two events, say A and B, is

P(A\ or\ B)=P(A\cup B)=P(A)+P(B)-P(A\cap B)

Compute the value of P (U or V) as follows:

P(U\ or\ V)=P(U\cup V)\\=P(U)+P(V)-P(U\cap V)\\=0.27+0.56-0\\=0.83

Thus, the value of P (U or V) is 0.83.

7 0
3 years ago
Read 2 more answers
Could someone please help me find the domain and range of the equation?...and B-64 a. Please??
alexandr1967 [171]
<h3>B-61. C=</h3><h3><u>Domain:</u></h3>

0 < x < ∞

or

x > 0

<h3><u>Range:</u></h3>

y ≥ 500

<h3>B-64. A=</h3>

9 − 3 = 4 − 3

5 − 3 = −3

5 = 0

= 0

Hope this helps you ! :)

6 0
2 years ago
What is the value of the 24th term in the following arithmetic sequence?
lorasvet [3.4K]

Answer:

Option B

Step-by-step explanation:

a_{n}=a_{1} +d(n-1)\\a_{n}=-9  +7(n-1)\\a_{24}=-9  +7(24-1)\\a_{24}=-9  +7(23)\\a_{24}=-9 + (161)\\\\a_{24}=152\\

4 0
2 years ago
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Rafael has a bag of marbles, there are 5 green marbles, 6 red marbles, and 4
yulyashka [42]

The probability of getting red marble from the consider withdrawal of a marble is 0.107 approximately.

<h3>How to calculate the probability of an event?</h3>

Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.

Then, suppose we want to find the probability of an event E.

Then, its probability is given as

P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}

where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.

Given that:

The bag contains:

  • 5 green marbles,
  • 6 red marbles,
  • 45 white marbles.
  • Rafael draws one marble at random

Since he draws one marbel, thus, only one colored marble would come out.

Let we suppose we've to find P(red marble coming out).

Then, if we take:

E = event of Rafael drawing a red marble,

then E can be done in 6 ways as there are 6 red marbles to choose from.

Also, withdrawal of 1 marble (of any color) can be done in (5+6+45 = 56) 56 ways.

Thus, we get:

P(E) = P(\text{Choosing a red marble}) = \dfrac{6}{56} = \dfrac{3}{28} \approx 0.107

Thus, the probability of getting red marble from the consider withdrawal of a marble is 0.107 approximately.

Learn more about probability here:

brainly.com/question/1210781

#SPJ1

3 0
2 years ago
An online spinner has two colored regions--blue and yellow. according to the website, the probability that the spinner lands in
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Answer:

right skewed

Step-by-step explanation:

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