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galben [10]
2 years ago
9

I need help with math please!!!! 77-99+33 divided by 6

Mathematics
1 answer:
Alona [7]2 years ago
7 0

Answer:

try with

77 - 99  + 33 \div 6

to calculate so you can find the answer thanks me later

Step-by-step explanation:

<h2><em><u>carry </u></em><em><u>on </u></em><em><u>learning</u></em></h2>
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what would be an outlier if added to the data set below? 507, 586, 499, 542, 615, 600, 561, 519 A.487 B.535 C.610 D.380
Trava [24]
I am pretty sure the answer is F
5 0
4 years ago
D<br> Find mZW.<br> X<br> WK (11x - 29)<br> Z<br> (6x + 5)<br> mZW
Artist 52 [7]

Answer:

m<W = 103°

Step-by-step explanation:

First, find the value of x

m<W + m<Y = 180° (opposite angles in a cyclic quadrilateral are supplementary)

11x - 29 + 6x + 5 = 180 (substitution)

Add like terms

17x - 24 = 180

Add 24 to both sides

17x = 180 + 24

17x = 204

Divide both sides by 17

17x/17 = 204/17

x = 12

Find m<W:

m<W = 11x - 29

Plug in the value of x

m<W = 11(12) - 29 = 132 - 29

m<W = 103°

3 0
3 years ago
S = p/(q + p(1 − q)) solve for q
saveliy_v [14]
S = p/(q +p -pq)
q +p -pq = p/s
q -pq = p/s - p
q(1-p) = p/s - p
q = (p/s - p) / (1-p)

8 0
4 years ago
Read 2 more answers
determine weather y varies directly with x. if so, find the constant variation and write the equation
REY [17]

Answer:

Yes, k = 1/3 and y = 1/3x

Step-by-step explanation:

\text{The given line passes through the origin, hence it has equation of the form:}\\y=kx

\text{Therefore y varies directly as x.}The line passes through the point (3,1)}

\text{This implies that,}

1=k(3)\\k=\frac{1}{3}\text{Hence the constant of variation is} ⇒ \frac{1}{3}

The equation would be ⇒ y=\frac{1}{3} x

5 0
2 years ago
omposite figure is divided into two congruent trapezoids, each with a height of 4 cm. 2 trapezoids. Both trapezoids have base le
adelina 88 [10]

Answer:Option C:

64 \ cm^2 is the area of the composite figure

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

b_1=10 \ cm

b_2=6 \ cm and

h=4 \ cm

Area of the trapezoid = \frac{1}{2} (b_1+b_2)h

Substituting the values, we get,

A=\frac{1}{2} (10+6)4

A=\frac{1}{2} (16)4

A=32 \ cm^2

Thus, the area of one trapezoid is $32 \ {cm}^{2}$

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2

Thus, the area of the composite figure is 64 \ cm^2

Step-by-step explanation:

4 0
3 years ago
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