Answer:
m<W = 103°
Step-by-step explanation:
First, find the value of x
m<W + m<Y = 180° (opposite angles in a cyclic quadrilateral are supplementary)
11x - 29 + 6x + 5 = 180 (substitution)
Add like terms
17x - 24 = 180
Add 24 to both sides
17x = 180 + 24
17x = 204
Divide both sides by 17
17x/17 = 204/17
x = 12
Find m<W:
m<W = 11x - 29
Plug in the value of x
m<W = 11(12) - 29 = 132 - 29
m<W = 103°
S = p/(q +p -pq)
q +p -pq = p/s
q -pq = p/s - p
q(1-p) = p/s - p
q = (p/s - p) / (1-p)
Answer:
Yes, k = 1/3 and y = 1/3x
Step-by-step explanation:
⇒ 
The equation would be ⇒ 
Answer:Option C:
64 \ cm^2 is the area of the composite figure
It is given that the composite figure is divided into two congruent trapezoids.
The measurements of both the trapezoids are
b_1=10 \ cm
b_2=6 \ cm and
h=4 \ cm
Area of the trapezoid = \frac{1}{2} (b_1+b_2)h
Substituting the values, we get,
A=\frac{1}{2} (10+6)4
A=\frac{1}{2} (16)4
A=32 \ cm^2
Thus, the area of one trapezoid is $32 \ {cm}^{2}$
The area of the composite figure can be determined by adding the area of the two trapezoids.
Thus, we have,
Area of the composite figure = Area of the trapezoid + Area of the trapezoid.
Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2
Thus, the area of the composite figure is 64 \ cm^2
Step-by-step explanation:
