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elixir [45]
4 years ago
9

Serenity works in a department store selling clothing. She makes a guaranteed salary of $300 per week, but is paid a commision o

n top of her base salary equal to 25% of her total sales for the week. How much would Serenity make in a week in which she made $1075 in sales? How much would Serenity make in a week if she made x dollars in sales?
Mathematics
1 answer:
madam [21]4 years ago
5 0

Answer:

$568.75

Step-by-step explanation:

Serenitys salary s is given by the equation:

s = 300 + 0.25*x

In case of x = 1075:

s = 300 + 0.25*1075 = 568.75

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What is the answer for. -3x > -15
lana [24]

Answer:

x<5

Step-by-step explanation:

-3x > -15

Divide -3 on both sides:

\frac{-3x}{-3} >\frac{-15}{-3}

x<5

*Note the sign switches because

the x is negative. The sign only

switches when the number you

are dividing by is negative.*

7 0
3 years ago
Proove that <br>1/1-sin theta + 1/1+cos theta = 2×sec square theta ​
Rina8888 [55]

Step-by-step explanation:

We need to prove that,

\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}=2\times \sec^2\theta

Taking LHS,

\dfrac{1}{1-\sin\theta}+\dfrac{1}{1+\sin\theta}\\\\=\dfrac{(1+\sin\theta)+(1-\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}\\\\=\dfrac{2}{1-\sin^2\theta}\\\\\text{As}\ 1-\sin^2\theta=\cos^2\theta\\\\=\dfrac{2}{\cos^2\theta}\\\\\text{As}\ \dfrac{1}{\cos^2\theta}=\sec^2\theta\\\\=2\sec^2\theta\\\\=RHS

Hence, LHS = RHS.

4 0
3 years ago
I really help and an explanation for this. It is due today :)
n200080 [17]

Answer:

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7 0
4 years ago
How to compare and contrast factors and multiples
ValentinkaMS [17]
I couldn't able to understand ur question , give an example problem
4 0
4 years ago
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Solve the equation for x, where x is a real number (5 points): <br> -2x^2 + 5x - 10 = 3
KatRina [158]
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                                      x = [ -b ± √(b^2 - 4ac) ] / (2a)
                                      x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
                                      x = [-5 ± √(25 - (104) ) ] / ( -4 )
                                      x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
3 0
3 years ago
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