Answer:
I believe this is pathgorean theorem, which I did at the beginning of alegbra last year. It is basically finding the missing side of a triangle. (Trust me some of the easiest stuff you do all year) Below are my notes from last year. I hope it helps! Good Luck!!!
Step-by-step explanation:
Given two sides
If you know two other sides of the right triangle, it's the easiest option; all you need to do is apply the Pythagorean theorem:
a² + b² = c²
if leg a is the missing side, then transform the equation to the form when a is on one side, and take a square root:
a = √(c² - b²)
if leg b is unknown, then
b = √(c² - a²)
for hypotenuse c missing, the formula is
c = √(a² + b²)
31/50
Showing the work
Rewrite the decimal number as a fraction with 1 in the denominator
0.62=0.62/1
Multiply to remove 2 decimal places. Here, you multiply top and bottom by 10^2=100
0.62/1*100/100=62/100
Find the Greatest Common Factor (GCF) of 62 and 100, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF=2,
62/2
_____=31/50
100/2
Therefore
X=31/50
In conclusion,
0.62=31/50
93.5 + 8.7 = 102.2
Hope this helps! :)
Answer:
A&C
Step-by-step explanation:
Three loaves since that’s what’s available to the family
