Answer:
Number of different selection = 50C6
Number of different selection = 50 x 49 x 48 x 47 x 46 x 45
Number of different selection = 15 890 700
Step-by-step explanation:
Answer:
<h2>x = -4 and y = -1 → (-4, -1)</h2>
Step-by-step explanation:
Answer:
Class 7A collected 4.8 ounces of pure gold.
Step-by-step explanation:
<u>Key skills required are: Percentages, Multiplication</u>
<u />
- We only need the information about Class 7A. They collected 40 oz that contains 12% gold.
- In other words, this means that 12% of that 40 oz gold sand is pure gold.
Here we have to do 12% x 40 to find the number of oz of pure gold. We first have to convert 12% into a decimal. Divide it by a 100 (or move the decimal point 2 places to the left) and you will get 0.12.
<em>Do 0.12 x 40 and you will get 4.8</em>
Therefore, there are 4.8 oz of pure gold in Class 7A's gold sand
Answer:
true
Step-by-step explanation:
cuz it has () so u can multi
Answer:
El perímetro del triángulo rectángulo es aproximadamente 29.627.
Step-by-step explanation:
Las coordendas de los vértices del triángulo rectángulo son 
, 
y 
. En primer lugar, determinamos las longitudes de los segmentos AB, BC y AC por el Teorema de Pitágoras:
![AB = \sqrt{(-8-1)^{2}+[4-(-2)]^{2}}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%28-8-1%29%5E%7B2%7D%2B%5B4-%28-2%29%5D%5E%7B2%7D%7D)
![BC = \sqrt{[5-(-8)]^{2}+(2-4)^{2}}](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B%5B5-%28-8%29%5D%5E%7B2%7D%2B%282-4%29%5E%7B2%7D%7D)
![AC =\sqrt{(5-1)^{2}+[2-(-2)]^{2}}](https://tex.z-dn.net/?f=AC%20%3D%5Csqrt%7B%285-1%29%5E%7B2%7D%2B%5B2-%28-2%29%5D%5E%7B2%7D%7D)
El perímetro del triángulo (
) es la suma de todos estos segmentos:
El perímetro del triángulo rectángulo es aproximadamente 29.627.
