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3 years ago

Solve the system by substitution

Mathematics

1 answer:

Vikentia [17]3 years ago

3 0

Answer:

I think its:

Q1= x=(9+y)/2

Q2= x=(-20-6xy)/4

Step-by-step explanation:

Q1)

X-y=9

2x-y=9

2x=9+y

x=(9+y)/2

Q2)

4x-2y=-20

4x-2(-3x)=-20

4x+6xy=-20

4x=-20-6xy

x=(-20-6xy)/4

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What is the equation x=y+z solved for z

sertanlavr [38]

X=y+z
subtract y from both sides
-y+x=z that is your answer

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3 years ago

Can someone help me plzzz

Ann [662]

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3 0

3 years ago

For a saturday matinee, adult tickets cost $5.50 and kids under 12 pay only $4.00. if 70 tickets are sold for a total of $310, h

irina1246 [14]

20 adults and 50 kids.
-
Ax+By=C [Use the standard form of a linear equation]
x+y=C so, x+(C-x)=C [also use this formula]
.
$5.50x+$4.00y=$310 [plug-in the values]
Since x+(C-y)=C, than x+y=70 or x+(70-x)=70
.
5.50x+4.00(70-x)=310 [substitute (70-x) for y and simplify]
5.50x+280-4x=310
5.50-4=310-280 [solve for x]
1.5x=30
x=20 adults
and
y=(70-x)=70-20=50 kids under 12.

4 0

3 years ago

How is this written in an expanded version?

Yuri [45]

Powers distribute over multiplications:

$(ab)^c = a^c\cdot b^c$

So, you have

$(3k^5)^2 = 3^2 \cdot (k^5)^2$

Now, $3^2$ is simply 9.

As for $(k^5)^2$ , we have to use the rule

$(a^b)^c = a^{bc}$

to get

$(k^5)^2=k^{5\cdot 2}=k^{10}$

So, the final answer is

$(3k^5)^2 =9k^{10}$

5 0

3 years ago

Read 2 more answers

I need help plz cmon

PolarNik [594]

Answer: 84

Step-by-step explanation:

4 x 21 is 84 a fraction can be simplified and be a whole number so if 84 divided by 4 it will be 21 if you want to write it as a fraction it will be 21/1 which is equal to 21

Did it help? :)

7 0

3 years ago