All categories

3 years ago

Round 223 to the nearest 10

1 answer:

8 0

220. Think of it this way: 5 and above, give it a shove, 4 and below, keep it down low. That means that if the last number is five or above, push it up to the nearest 10, and if the last number is four or below, round to the lowest 10.

You might be interested in

If U = (all positive integers) and A = {x\X € U and x is an odd positive integer), which describes A?

Solnce55 [7]

Answer:

Step-by-step explanation:

A={1,3,5,7,9,...}

4 0

3 years ago

Express 0.7 as a rational number.

quester [9]

7/10 is the rational number :)

6 0

4 years ago

Find the mean for the following data set: 5, 3, 6, 8, 1, 1 *

Zarrin [17]

Answer:

add all the numbers

which will get you 24

then divide by how many numbers you got which will give you 6

the answer is six

Step-by-step explanation:

Hope this helps :D

8 0

3 years ago

Read 2 more answers

How did the transformation of ()=f of , open x close . equals , x squared to ()=−g of , open x close . equals , x squared , minu

Nikolay [14]

The intercepts are the points where the graph crosses the x or y-axis

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3

The functions are given as:

$f(x) = x^2$

$g(x) = x^2 - 3$

Function f(x)

$f(x) = x^2$

The x-intercept is calculated as follows:

Set f(x) to 0

$x^2 = 0$

Solve for x

$x = 0$

The y-intercept is calculated as follows:

Set x to 0

$f(0) = 0^2$

$f(0) = 0$

Hence, the intercepts are 0

Function g(x)

$g(x) = x^2 - 3$

The x-intercept is calculated as follows:

Set g(x) to 0

$x^2 - 3 = 0$

Solve for x

$x^2 = 3$

$x = \±\sqrt 3$

The y-intercept is calculated as follows:

Set x to 0

$g(x) = x^2 - 3$

$g(0) = 0^2 - 3$

$g(0) = - 3$

The x-intercepts are $\±\sqrt 3$ , while the y-intercept is -3

By comparing the intercepts of f(x) and g(x),

The x-intercepts changed from 0 to $\±\sqrt 3$ .
The y-intercepts changed from 0 to 3