Hello,
A=(4,2)
B=(2,8)
(AB)≡y-2=(x-4)*(8-2)/(2-4) ==> y=-3x+14
(BC)≡y-8=(x-2)*1/3 ==> y=1/3 x+22/3
A=(4,2)
B=(2,8)
(AB)≡y-2=(x-4)*(8-2)/(2-4) ==> y=-3x+14
(BC)≡y-8=(x-2)*1/3 ==> y=1/3 x+22/3
What is the size of the angle, below? please help me
1 answer:
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Answer:
Step-by-step explanation:
x^2+y^2=r^2 --> subtract x^2 to other side
y^2=r^2-x^2 --> square root both sides
y=sqrt(r^2-x^2)