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antiseptic1488 [7]
3 years ago
14

Where is the balance point located? A B C D E

Mathematics
2 answers:
grigory [225]3 years ago
4 0
The answer is C I did this
Mandarinka [93]3 years ago
3 0

Answer:

C i hope it helps I might be wrong do

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Please help me this question
Annette [7]

Step-by-step explanation:

Hey there!

The given point is (8,-3) as (x1,y1) and slope (m) = -3/4.

<u>Note</u><u>:</u><u> </u><u>use</u><u> </u><u>one</u><u> </u><u>po</u><u>int</u><u> formula</u><u> for</u><u> </u><u>f</u><u>inding</u><u> </u><u>the</u><u> </u><u>eq</u><u>uation</u><u>.</u>

(y - y1) = m(x - x1)

<u>Pu</u><u>t</u><u> all</u><u> values</u><u>.</u>

<u>(y  + 3) =  -  \frac{ 3}{4} (x - 8)</u>

<u>Sim</u><u>plify</u><u> it</u><u>.</u>

<u>(y + 3) =   -  \frac{  3}{4} x - 8 \times  -  \frac{3}{4}</u>

<u>(y + 3) =  -  \frac{3}{4} x + 6</u>

<u>y  =  -  \frac{3}{4} x + 6 - 3</u>

<u>y =  -  \frac{3}{4} x + 3</u>

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>equation</u><u> is</u><u>;</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>3</u><u>/</u><u>4</u><u>x</u><u>+</u><u>3</u><u>.</u>

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
Um ok i need help pls give correct answers
vesna_86 [32]
-a) function 2, function 4
-b) function 4
-c) function 2
4 0
3 years ago
Read 2 more answers
The best approximation for square root of 110 is
N76 [4]
The best approximation is 10 because the two closest perfect squares to 110 is 100 and 121. the one that's closest to 110 though is 100. the square root of 100 is 10.
5 0
3 years ago
In the figure below, CD bisects m∠ACB, AB=BC, m∠BEC=90°, and m∠DCE=42°. Find the measure of ∠A.
vesna_86 [32]

Answer:  ∠A= 24\textdegree

Step-by-step explanation:

Since we have given that

CD bisects m∠ACB,

⇒  m∠ACD= m∠DCB =x (say)

And, AB=BC, m∠BEC=90°, and m∠DCE=42°

So,

m∠CAD=m∠ACD

In ΔDCE,

\angle DCE+\angle CED+\angle CDE=180\textdegree\\\\(\text{Sum of anlges in triangle is }180\textdegree)\\\\42\textdegree+90\textdegree+\angle CDE=180\textdegree\\\\132\textdegree+\angle CDE=180\textdegree\\\\\angle CDE=180\textdegree-132\textdegree\\\\+\angle CDE=48\textdegree

Now, in  ΔACD,

x+x=48\textdegree\\\\2x=48\textdegree\\\\\text{( Sum of interior anlges is equal to exterior angles )}\\\\x=\frac{48}{2}\\\\x=24\textdegree

Hence , ∠A= 24\textdegree

8 0
3 years ago
Read 2 more answers
Determine the x- and y-intercepts of each line x+3y=24
ivann1987 [24]
<span>Determine the x- and y-intercepts of each line x+3y=24
+ x=0, so y= 24:3=8 and we have </span><span>y-intercepts is 8
</span>+ y=0, so we have x=24, x<span>-intercepts is 24

Have fun</span>
4 0
4 years ago
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