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Dmitry_Shevchenko [17]
2 years ago
10

Suppose that we have this spinner. What is the probability of landing on 2 after landing on 5?

Mathematics
2 answers:
schepotkina [342]2 years ago
6 0

There are 5 numbers and only one of each number.

The probability of landing in 5 would be 1/5

The probability of landing in 2 would be 1/5


The probability of landing on 5 then 2 is 1/5 x 1/5 = 1/25 = 0.04 = 4%


answer = 4%

lora16 [44]2 years ago
4 0

Answer:

Answer above is correct.

Step-by-step explanation:

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The answer is not A can someone plz help me I’m not understanding it thank you it would be appreciated
jeka94

nswer:

209.8

Step-by-step explanation:

the bottom is = 11 * 5

two of the sides are 11 * 9.3 / 2    because they are triangles, and then times 2 because there are two of them

the other two sides are 10.5 * 5 / 2 , and the * 2 because there are two of them again.

(11 * 5) + (11 * 9.3 * 2 / 2) + (10.5 * 5 * 2 / 2) =209.8

6 0
3 years ago
If the discriminant of an equation is zero, which of the following is true of the
miss Akunina [59]

Answer:

Step-by-step explanation:

if the discriminate is 0, it means that both roots are the same. Not only that, but it also means that the roots are real. I would pick D, but realize that that is the expected answer and the answer could be B, depending on how the person writing the problem thinks about it.

5 0
3 years ago
How many grams of a 15 percent alcohol solution should be mixed with 40 grams of a 30 percent solution to obtain a
Akimi4 [234]

The number of  grams is 20 grams

Let x represent how  many grams of a 15 percent alcohol solution

15%x+30%.40/x+40

=25%

0.15x+0.4.30=0.25 (x+40)

0.15x+12=0.25x+10

0.15x-0.25x=10+12

-0.1x=-2

x=-2/-0.1

x=20

Inconclusion The number of  grams is  20 grams

Learn more here:

brainly.com/question/24750329

4 0
2 years ago
The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp
Anvisha [2.4K]

Answer:

  • Initial amount of the material is 67 kg
  • Hal-life is 83 hours

<u>The required equation is:</u>

  • m(x) = 67 * (1/2)^{x/83}, where m- remaining amount of the radioactive material, x - number of hours

<u>After 5 hours the material remains:</u>

  • m(5) = 67 * (1/2)^{5/83} = 64.260 (rounded)
4 0
2 years ago
Please Help 30 Points
Virty [35]

Answer:

Step-by-step explanation:

5 0
2 years ago
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