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svetoff [14.1K]
3 years ago
7

Three students were given the expression shown and were asked to take a common factor out of two of the terms. Use the drop-down

menus to complete the statements about whether each student's answer is an equivalent expression. Then choose an expression that is equivalent.
Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

Answer:

Calvin: incorrect, sign error

Greg: incorrect, has no relationship to the given expression

Ruben: incorrect, sign error

Equivalent expression: 7 92(4x -11)

Step-by-step explanation:

I hope this helps you :)

<em><u>-KeairaDickson</u></em>

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What are the solutions to the equation x^2-8x=24
Oduvanchick [21]
x^{2} - 8x = 24

Transposing the equation to give zero on the RHS:
x^{2} - 8x - 24 = 0

Since we can't factorise it directly, we must complete the square to yield any solutions:
x^{2} - 8x + ( \frac{8}{2})^2 - (\frac{8}{2})^2 - 24 = 0
(x^{2} - 8x + 16) - 16 - 24 = 0
(x-4)^2 - 40 = 0
(x-4)^2 = 40
x-4 = +/- \sqrt{40} ––> because square rooting yields a positive and negative solution.
x = 4 +/- \sqrt{40}
x = 4 +/- 2 \sqrt{10}

Correct me if I'm wrong anyone.
4 0
3 years ago
Need help with ixl please give right answer
lara [203]
Y = 8x - 11 using the slope-intercept form.
4 0
3 years ago
I’m completely confused.
Leviafan [203]
F(-2) = 7
f(0) = 6
f(6) = 3
f represents the function and the number in the parentheses is the input for the function, y on the graph is the output
6 0
2 years ago
Read 2 more answers
Answer!asap if you are a bot don't even respond
Tema [17]

Answer:

Step-by-step explanation:

Upon factoring all terms we are left with the product of

[(x-4)(x+6)(x-6)]/[5(x-6)(3x+5)(x-4)]

The (x-4)s and (x-6)s cancel out and we are left with

(x+6)/(5(3x+5)) which is also equal to

(x+6)/(15x+25)

6 0
3 years ago
What is the rate of change and initial value for the linear relation that includes the points shown in the table?
defon

The initial value: 25, rate of change: -5 ⇒ answer C

Step-by-step explanation:

The table:

→  x  :    1    :    3    :    5    :    7

→  y  :    20 :    10  :    0    :    -10

The linear relation between x and y is y = m x + b, where

  • m is the rate of change
  • b is the initial value

Let us use the table to find m and b

∵ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where (x_{1},y_{1})

   and (x_{2},y_{2}) are any two ordered pairs in the table

∵ (x_{1},y_{1}) = (1 , 20)

∵ (x_{2},y_{2}) = (3 , 10)

∴ m=\frac{10-20}{3-1}=\frac{-10}{2}=-5

∵ m is the rate of change

∴ The rate of change is -5

Substitute the value of m in the form of the linear relation

∴ y = -5 x + b

To find b substitute x and y in the equation by the coordinates of any points in the table, let us chose point (5 , 0)

∵ x = 5 and y = 0

∴ 0 = -5(5) + b

∴ 0 = -25 + b

- Add 25 to both sides

∴ 25 = b

∵ b represents the initial value

∴ The initial value is 25

The initial value: 25, rate of change: -5

Learn more:

You can learn more about the linear equation in brainly.com/question/4326955

#LearnwithBrainly

8 0
3 years ago
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