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Evgesh-ka [11]
3 years ago
10

We plan to construct a line segment through point P and perpendicular to line segment EF. What is the SMALLEST number of compass

adjustments with which this can be done? A) 1 B) 2 C) 3 D) 4
Mathematics
2 answers:
pantera1 [17]3 years ago
4 0
The answer to your question would be A, 1.
eimsori [14]3 years ago
3 0

Answer:

A) 1

Step-by-step explanation:

REmember that to create the perpendicular line segment to the segment EF you just have ot adjust the compass to three quarters and draw semi circular segments from points E and "F" that would intersect with eachother and from there to the other side of the segment you draw a line fomr the two points where the semi circles intersect with eachother. so you only need one adjustment to the compass.

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When Harper commutes to work, the amount of time it takes her to arrive is normally distributed with a mean of 24 minutes and a
Korvikt [17]

Answer:

\mu -2\sigma = 24-2*3= 18

\mu -2\sigma = 24+2*3= 30

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

Step-by-step explanation:

For this case we can define the random variable X as the amount of time it takes her to arrive to work and we know that the distribution for X is given by:

X \sim N(\mu = 24, \sigma =3)

And we want to use the empirical rule to estimate the middle 95% of her commute times. And the empirical rule states that we have 68% of the values within one deviation from the mean, 95% of the values within two deviations from the mean and 99.7 % of the values within 3 deviations from the mean. And we can find the limits on this way:

\mu -2\sigma = 24-2*3= 18

\mu -2\sigma = 24+2*3= 30

So then we can conclude that we expect the middle 95% of the values within 18 and 30 minutes for this case

7 0
3 years ago
There are eight shirts in your closet, three blue, two are black, one is green, and two are white. You randomly select one to we
Maru [420]

The probability of wearing blue shirts on both days is 3/28.

<h3>What is probability?</h3>

Probability is the measure of the likelihood of an occurrence.

Given:

8 shirts are available out of which 3 are blue, 1 is green and 2 are white.

P(blue on Monday) = 3/8

Now, 7 shirts are left to wear on Tuesday

P(blue on Tuesday) =2/7

So,

the probability of wearing blue shirts on both days = 3/8 * 2/7 = 3/28

Learn more about probability here:

brainly.com/question/24756209

#SPJ1

4 0
2 years ago
£440 is divided between David, Mark &amp; Henry so that David gets twice as much as Mark, and Mark gets three times as much as H
Lesechka [4]

Mark received £ 132

<em><u>Solution:</u></em>

Given that £440 is divided between David, Mark & Henry

Let "d" be the share of david

Let "m" be the share of mark

Let "h" be the share of henry

Total amount is 440

Therefore,

share of david + share of mark + share of henry = 440

d + m + h = 440 ------- eqn 1

<em><u>David gets twice as much as Mark</u></em>

d = 2m ----- eqn 2

<em><u>Mark gets three times as much as Henry</u></em>

m = 3h

h = \frac{m}{3}  ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

2m + m + \frac{m}{3} = 440\\\\\frac{6m + 3m + m}{3} = 440\\\\10m = 1320\\\\m = 132

Thus Mark received £ 132

8 0
3 years ago
Graph the solution set. please help
Ratling [72]

Answer:

In the attachment.

Step-by-step explanation:

Rewrite x\geq-3y-6 as a y\geq -\frac{1}{3}x-2. Then mark each set with different color and take the intersection of these.

7 0
2 years ago
Cassie bought a pair of loafers for $29.95. Tights were on sale for 3 pairs for $10.00. She gave the clerk $60.00. How much chan
monitta

Answer:

$20.05 is Cassie's change

Step-by-step explanation:

60.00-29.95=30.05

30.05-10=20.05

5 0
3 years ago
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