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Crazy boy [7]
2 years ago
7

18/2x-6step by step please ​

Mathematics
1 answer:
Anna [14]2 years ago
5 0

Answer:

\frac{9}{x-3}

Convert the problem into split up expressions.

\frac{18}{2}(x - 6)

Take both 6 and 18's most common factor here, 2, and divide by 2 to simplify.

\frac{18}{2} = 9\\\\\frac{6}{2} = 3

Cancel.

18 becomes 9

6 becomes 3

The equation turns into:

\frac{9}{x - 3}

<em>note that because we, "canceled" 2, that also means it does not appear in the simplified form since it was a factor.</em>

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Answer:

D,12cm

Step-by-step explanation:

100 percent/TRUST

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3 years ago
I need help please and thank you
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Oof I’m not quite sure how to do that
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Sam has the lead role in the school play. He still has to memorize 1/2 of his lines. Suppose Sam memorizes 1/3 of his lines toda
DaniilM [7]

Answer: 1/6

Step-by-step explanation:

Since Sam has to memorize 1/2 of his lines and he memorizes 1/3 of his lines today, the fractions of his lines that he has left to memorize will be gotten by subtracting 1/3 from 1/2. This will be:

= 1/2 - 1/3

= 3/6 - 2/6

= 1/6

Therefore, he has 1/6 of his lines left to memorize.

4 0
2 years ago
Read 2 more answers
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
7 0
3 years ago
Find the value of X.
klemol [59]

Answer:

I think answer is 3

Step-by-step explanation:

BD = DA

BE = EC

Now, BD/BE = DA/EC

or, x + 5/2x = 4/3

or, 3x + 15 = 8x

or, 15 = 8x - 3x

or, 15 = 5x

or, 15/5 = x

or, 3 = x

Therefore x = 3 <u>Ans</u>

5 0
3 years ago
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