How do i solve 3(d-8)-5=9(d+2)+1
2 answers:
3(d-8)-5 = 9(d+2) + 1
3d - 24 - 5 = 9d + 18 + 1
3d - 29 = 9d + 19
3d = 9d + 48
-6d = 48
48/-6 = -8
d = -8
D=-8
3(-8-8)-5 3(-16)-5=-48-5=-53
9(-8+2)+1=9(-6)+1=-54+1=-53
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