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3 years ago

What is this for 2nd grade math. 247+?=673

Mathematics

1 answer:

icang [17]3 years ago

7 0

Answer:

426

Step-by-step explanation:

Subtract 247 from 673 to get 426

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Tom shared out some money between his three children in the ratio 5:3:2. He later had an extra €6

andrew-mc [135]

Answer:

Step-by-step explanation:

Easy 54320

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3 years ago

A 1 3/4 kg fish weighed 1 3/16 kg after it was cleaned. how much was the decreased in weight of the fish.

joja [24]

Answer:

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Step-by-step explanation:

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3 years ago

What can you conclude about lineDB?

Ilia_Sergeevich [38]

line DB bisects line AC

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4 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago

Will Mark Brainlest. (find the domain of following relation for the given range) step by step

mr_godi [17]

Step-by-step explanation:

I suppose you mean find the range for the following domain. Because when

g(x) is given the value of X

we are trying to solve the output value which is range.

If you want to solve for the domain, the question should give

g(x) = y

and provide the value of y.

X³+X²-X-2

Substitute

X=(-1)

-1+1-(-1)-2

= -1

g(-1)= -1

Substitute

X=(2)

8+4-2-2

g(2)= 8

Substitute

X=(1)

1+1-1-2

=-1

g(1)= -1

g(2)+g(1)

=8-1

5 0

3 years ago