<span>X^2- 4x- 6y- 14=0
6y = x^2 - 4x - 14
Divide through by 6:-
y = (1/6)x^2 - (2/3)x - 7/3</span>
2n+14=14+2n so this one as an infinite number of solutions. The second one 1-x=-x-6 so you add x on both sides which results in it having no solutions.
Answer:
Step-by-step explanation:
We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).
p = 12/100 = 0.12
number of success, x = 20
n = 200
the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)
From the binomial probability calculator,
P(x ≥ 20) = 0.84
Answer:
1111111110
Step-by-step explanation:
45 is 9, and 5.
9 divisibility rule: Digits have to add up to 9.
We know this has to be 1's and 0's.
So there has to be 9 1's.
111111111.
5 divisibility rule: Last digit has to be 0 or 5.
1111111110 will be our final answer.
Wait- let's check if it's divisible. Using a calculator, this determines it does work.
Enjoy.
Let us assume the first number = x
Then the second number = 5x -2
The third number = x + 4
The total number that needs to be divided into three parts is 219
Then we can write the equation as
x + 5x - 2 + x + 4 = 219
7x + 2 = 219
7x = 219 - 2
7x = 217
x = 217/7
= 31
Then
First number = 31
Second number = 5x - 2
= (5 * 31) - 2
= 155 -2
= 153
Third number = x + 4
= 31 + 4
= 35
So the three numbers are 31, 153 and 35.
