Please, group your sets of numbers, using { } notation or at least semicolons ( ; ). Thanks.
Looking at what I think is your first set: { sqrt(4), sqrt(5), sqrt(16) }
Square each of these and then subst. the results into the Pythagorean Theorem:
{ 4, 5, 16 } Do 4 and 5 when added together result in 16? NO.
Therefore, { sqrt(4), sqrt(5), sqrt(16) } does not produce a right triangle.
Your turn. Pick out the next 3 numbers and test them using the Pyth. Thm.
Answer:
2^3·2^2 = 2^3+2 = 2^5
Step-by-step explanation:
Diego was trying to write 2^3 · 2^2
He wrote 2^3·2^2 = 2^3*2 = 2^6
But this is wrong because when bases are same exponents are added.
This is the law of exponents.
The correct form would be
2^3·2^2 = 2^3+2 = 2^5
For understanding it better we can write it like this
2^3·2^2 =
There are 3 two and 2 twos .When totaled there are 5 two not 6 twos.
-16k+56 check photo for steps and please mark as brainliest if i helped! thanks c:
Answer:
Step 1: Simplify both sides of the equation.
−7f=12
Step 2: Divide both sides by -7.
−7f
−7
=
12
−7
f=
−12
7
Step-by-step explanation
sorry for the answer like this i couldnt find the fractions but the answer is f=-12/7 sorry :(
8•25•23=
25 eight times is 25 four times + 25 four more times
((25•4)+(25•4))•23= (100+100)•23= 200•23= 2•23•100= 46•100= 4,600
