Answer:
you are actually incorrect the answer is 2π
No. which have factors 2 & 5 have 2 & 5 as their prime factor
therefore, No. are :
2*5 = 10
2*5*2 = 20
2*5*3 = 30
Let the price of a ticket be originally T dollars, and the number of clients be N.
let the price decrease by x 3-dollars.
"there is an average increase of 4 people for every $3 decrease on the price of the ticket."
means:
if the price is decreased by 1-3$:
then N become N+4, and T becomes T-3
if the price is decreased by 2-3$:
then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3
So if the price is decrease by x-3 dollars:
N becomes N+4x, and T becomes T-3x
"A circus owner sells an average of 340 tickets when the price of a ticket is $75."
In this case N=340, and T=75$
If the owner does not change the price ticket, x=0, the revenue is 340*75,
If the owner decreases the price of the tickets by x-3$, then the revenue will be
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,
If R is the function of the revenue depending on x, then
R(x)=(340+4x)(75-3x) dollars
Answer: R(x)=(340+4x)(75-3x) dollars
Answer:
0=2
There are no solutions
Step-by-step explanation:
Answer:
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Step-by-step explanation:
