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velikii [3]
3 years ago
5

A theme park had 1099 visitors in 3 days.There were twice as many visitors on saturday than on Friday.There were 234 more visito

rs on Sunday than on Saturday.How many visitors were there on Saturday
Mathematics
1 answer:
Blababa [14]3 years ago
3 0

Answer: there were 692 visitors on Saturday.

Step-by-step explanation:

Let x represent the number of visitors that were there on Friday.

Let y represent the number of visitors that were there on Saturday.

Let z represent the number of visitors that were there on Sunday.

The theme park had 1099 visitors in 3 days. It means that

x + y + z = 1099- - - - - - - - - - - - - -1

There were twice as many visitors on saturday than on Friday. This means that

y = 2x

x = y/2

There were 234 more visitors on Sunday than on Saturday. This means that

z = y + 234

Substituting x = y/2 and z = y + 234 into equation 1, it becomes

y/2 + y + y + 234 = 1099

Cross multiplying by 2, it becomes

y + 2y + 2y + 468 = 2198

5y = 2198 - 468

5y = 1730

x = 1730/5

x = 346

y = 2x = 2 × 346

y = 692

z = y + 234 = 692 + 234

z = 926

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Let, speed of 1st bicyclist is x.

So, speed of 2nd bicyclist is x-3 .

We know, relative speed when two objects moves towards each other :

v = x + ( x-3 )\\\\v = 2x - 3

Now, distance travelled in 3 hours is (98-2) miles .

So,

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Therefore, speed of bikes are 17.5 mph and 14.5 mph.

Hence, this is the required solution.

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3 years ago
1. An orange is peeled . 18 identical sectors are found . What angle do does each semicircular surface make with another in a wh
KatRina [158]

Answer:

<h3>#1</h3>

<u>Since the circle covers 360°, each sector will be:</u>

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The same angle will be made between two adjacent semicircles.

<h3>#2</h3>

The points have same latitude but different longitude.

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8 0
2 years ago
AB is tangent to the circle k(O) at B, and AD is a secant, which goes through center O. Point O is between A and D∈k(O). Find m∠
drek231 [11]

Answer:

∠BAD=20°20'

∠ADB=34°90'

Step-by-step explanation:

AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.

Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus

∠BOD+∠BDO+∠DBO=180°

∠BDO+∠DBO=180°-110°20'=69°80'

∠BDO=∠DBO=34°90'

So ∠ADB=34°90'

Angles BOD and BOA are supplementary (add up to 180°), so

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In right triangle ABO,

∠ABO+∠BOA+∠OAB=180°

90°+69°80'+∠OAB=180°

∠OAB=180°-90°-69°80'

∠OAB=20°20'

So, ∠BAD=20°20'

5 0
3 years ago
Read 2 more answers
Can someone help Find the surface area
ankoles [38]

Answer:

1861.39 cm²

Step-by-step explanation:

Given:

d = 15 cm

radius (r) = ½(15) = 7.5 cm

Height = 32 cm

Surface area of a cylinder = 2πrh + 2πr²

Plug in the values

Surface area = 2*π*7.5*32 + 2*π*7.5²

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7 0
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yan [13]

Answer:

Estelle paid $104 in total.

Step-by-step explanation:

15% of $80.00 is 12. So add 12 two times to 80 because of 15% sales tax and 15% tip.

3 0
3 years ago
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