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s2008m [1.1K]
2 years ago
7

The athletic department wants to paint the school’s mascot logo on the gym wall. They start by painting a solid blue circle on t

he wall. The circle has an area of 78.5 ft^2.`What is the radius of the circle?
Mathematics
1 answer:
Murrr4er [49]2 years ago
8 0

Answer:

divide the area by 2 to get answer

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A scuba diver starts at 29 meters below the surface and descends until he reaches 67 meters below sea level. How many meters did
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38 meters

explanation:
you subtract 29 from 67
(67-29=38)
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PLS HELP ME <br> what is the equation I really need it
son4ous [18]

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Step-by-step explanation:

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3 years ago
In △ABC, ∠ABC = 60○
Temka [501]

A given shape that is <u>bounded</u> by three sides and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of PB is <u>8.0</u> units.

A given <u>shape</u> that is <em>bounded</em> by three <em>sides</em> and has got three <em>internal angles</em> is referred to as a <em>triangle</em>. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The<em> sum</em> of the <u>internal</u> <u>angles</u> of any triangle is 180^{o}.

In the given question, point P is such that <APB = <APC = <BPC = 120^{o}. Also, line PB bisects <ABC into two <u>equal</u> measures. Thus;

<ABP = 30^{o}

Thus,

<ABP + <APB + <BAP = 180^{o}

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<BAP = 180^{o} - 150

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Apply the <em>Sine rule</em> to determine the <u>value</u> of <em>PB</em>, such that;

\frac{AP}{Sin B} = \frac{BP}{Sin30}

\frac{8}{Sin30} = \frac{BP}{Sin 30}

BP = \frac{8*Sin30}{Sin 30}

     = \frac{4}{0.5}

BP = 8.0

Therefore, the <u>value</u> of <u>BP</u> = 8 units.

For more clarifications on applications of the Sine rule, visit: brainly.com/question/15018190

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8 0
2 years ago
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Vladimir [108]

Answer:

  25 minutes 42 seconds

Step-by-step explanation:

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It will take ...

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You can shower for about 25 minutes 42 seconds.

3 0
3 years ago
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Make x the subject of the formula if a/b-x=b/a+x​
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s the question like that?

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a- x = b<u> </u><u>+</u> x .

b. a

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