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hodyreva [135]
3 years ago
5

156 revolutions in 180 seconds. how many revolutions in 2 minutes

Mathematics
1 answer:
Alona [7]3 years ago
4 0
180 seconds is 3 minutes. If you divide 156 by 3, you will get 52. If you are looking for 2 minutes, you have to multiply 52 by 2. The answer is 104 revolutions in 2 minutes.
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What is 3(x-4)+6=5(x-1)+1 equal to?
AleksandrR [38]

____________________________________________________

Answer:

x = -1

____________________________________________________

Step-by-step explanation:

Solve for x in the equation: 3(x-4)+6=5(x-1)+1

3(x-4)+6=5(x-1)+1\\\\\text{Distribute the 3}\\\\3x - 12 + 6 =5(x-1)+1\\\\\text{Distribute the 5}\\\\3x - 12 + 6 =5x-5+1\\\\3x - 12 + 6 =5x-4\\\\3x - 6 =5x-4\\\\\text{Subtract 5x to both sides}\\\\-2x-6=-4\\\\\text{Add 6 to both sides}\\\\-2x=2\\\\\text{Divide by -2}\\\\x=-1

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3 0
3 years ago
The third term of an arithmetical progression is 7, and the seventh term is 2 more than 3 times the third term.Find the first te
Sphinxa [80]
General formula for n-th term of arithmetical progression is

a(n)=a(1)+d(n-1).

For 3d term we have

a(3)=a(1) +d(3-1),  where a(3)=7
7=a(1)+2d

For 7th term we have
a(7)=a(1) +d(7-1)
a(7)=a(1) + 6d

Also, we have that the <span>seventh term is 2 more than 3 times the third term,
a(7)=3*a(3)+2= 3*7+2=21+2=23

So we have, </span>a(7)=a(1) + 6d and a(7)=23. We can write
23=a(1) + 6d.

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23=a(1) + 6d
<span> - (7=a(1)+2d)
</span>
16 = 4d
d=4,

7=a(1)+2d

7=a(1)+2*4
a(1)=7-8=-1
a(1)= - 1

First term a(1)=-1, common difference d=4.

Sum of  the 20 first terms is
S=20 * (a(1)+a(20))/2

a(1)=-1
a(n)=a(1)+d(n-1)
a(20) = -1+4(20-1)=-1+4*19=75

S=20 * (-1+75)/2=74*10=740

Sum of 20 first terms is 740.
3 0
3 years ago
which of the following shows the polynomial below written in decreasing order 5x^3-x+9x^7+4+3x^11 HELLLPPPPPPPPPPPPP a.3x^11+9x^
ValentinkaMS [17]

Answer:

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Step-by-step explanation:

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The answer should be this, but I couldn't find a match for it in the answer box.

7 0
3 years ago
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