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Ivenika [448]
2 years ago
6

Brainliest and show work on how to do all 3

Mathematics
2 answers:
Tamiku [17]2 years ago
8 0

Answer:

10. 91.08mm

11. 33.12in

12. 41.4yd

Step-by-step explanation:

To find the answer to each, we first need to calculate the circumference:

(use 3.14 for π)

(2 * Diameter) * π = Circumference

Then half the circumference (because it is a semicircle) and add it to the diameter once again to accommodate for the middle line.

(Circumference / 2) + Diameter

Do this for each semi-circle as shown here:

10. (2 * 22) * 3.14 = 138.16

(138.16 / 2) + 22 = 91.08

11. (radius is given so double the middle)

(2 * (2 * 4)) * 3.14 = 50.24

(50.24 / 2) + 16 = 33.12

12. (2 * 10) * 3.14 = 62.8

(62.8 / 2) + 10 = 41.4

ddd [48]2 years ago
3 0

Answer:

Question 1: 34.56 mm

Question 2: 12.57 in

Question 3: 15.70 yd

Step-by-step explanation:

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Equation of the line passing through (7,5) and (1, 2)​
Trava [24]

Answer:

y = \frac{1}{2}x + \frac{3}{2}

Step-by-step explanation:

Assuming this is a linear equation in the form of y = mx + b, we can first solve for the slope using \frac{y_2 - y_1}{x_2 - x_1}, for these points, the slope would be \frac{1}{2}. Now we plug in the points to get the equation:

plugging in (7,5), we get 5 = \frac{1}{2} ×7 + b

and solving for b, we get b = \frac{3}{2}

therefore, the equation of the line passing through (7,5) and (1,2) is y = \frac{1}{2}x + \frac{3}{2}.

hope this helps!

6 0
2 years ago
There are mangoes and oranges in a basket in the ratio 7: 11. If the total number of fruits is 720, then how many mangoes are th
lbvjy [14]

Answer:

280 mangoes

Step-by-step explanation:

sum the parts of the ratio, 7 + 11 = 18 parts

Divide the total by 18 to find the value of one part of the ratio.

720 ÷ 18 = 40 ← value of 1 part of the ratio , then

7 × 40 = 280 ← number of mangoes

8 0
2 years ago
Read 2 more answers
How to find the surface area of a prism??
Svetach [21]

Answer:

area of the two faces plus sides

6 0
2 years ago
Read 2 more answers
Plssssss answerrrrrrr
densk [106]
Don’t take my word for it but I think 3rd option
8 0
3 years ago
There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a \frac{3}{11} chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is \frac{8}{11}, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is\frac{2}{11}, and the probability of picking the second red ball is \frac{1}{10} and the probability of picking the green ball is\frac{1}{9}. We want to multiply thm again, as per the multiplication rule like the last problem.

\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}

5 0
3 years ago
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