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Scilla [17]
3 years ago
15

1. The lease common multiple of 3, 4, 6, and 8 is OA. 8. OB. 24. O C.72. OD.96.

Mathematics
2 answers:
swat323 years ago
8 0

Answer:

B. 24.

Step-by-step explanation:

3

4 = 2*2

6 = 2*3

8 = 2*2*2

LCM = 2*2*2*3 = 24

almond37 [142]3 years ago
3 0
The answer is ob.24
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What are the measures of anglss a, b, and c? Show your work and explain your answers.
alexgriva [62]

A is 40

B is 50

C is 115

Explanation, A is the same as the opposite, A + B + 90 = 180, and C + 65 = 180

4 0
3 years ago
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4 0
3 years ago
Assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles
OverLord2011 [107]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

A=P\left(1+r\right)^t

Then we get equation for motorcycles and cars as:

A=5.75\left(1+0.16\right)^t

A=3.5\left(1+0.25\right)^t

Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}

\left(\frac{1.25}{1.16}\right)^t>1.64285714286

t\cdot\ln\left(\frac{1.25}{1.16}\right)>\ln\left(1.64285714286\right)

t>\frac{\ln\left(1.64285714286\right)}{\ln\left(\frac{1.25}{1.16}\right)}

t>6.6436473051

Hence final answer is approx 6.644 years.

7 0
3 years ago
The price of one gallon of milk has increased from$3.24 to $4.06. What is the percentage increase
AlladinOne [14]
25.3% 

you have to do 4.06-3.24

then do that number divided by the original number then times by 100
8 0
3 years ago
Complete the steps of the derivation of the quadratic formula step 1: (x+b/2a)^2-b^2-4ac/4a^2=0
CaHeK987 [17]
(x+b/2a)^2-(b^2-4ac)/2a=0
Step 2:
Re-write the expression:
(x+b/2a)^2=(b^2-4ac)/4a^2

Step 3:
get the square root of both sides:
x+b/2a=sqrt[(b^2-4ac)/4a^2]

Step 4:
Simplifying we get:
x+b/2a=sqrt[b^2-4ac]/2a

Step 5
Make x the subject:
x=-b/2a+/-sqrt[b^2-4ac]/2a


5 0
4 years ago
Read 2 more answers
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