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Pavlova-9 [17]
2 years ago
12

How do you solve number 5?

Mathematics
1 answer:
Nimfa-mama [501]2 years ago
8 0

Answer:

B

Step-by-step explanation:

To get from 60 to 75, you multiply by a certain factor. That factor is 75/60 = 1.25. In percents this is 125%

60 * 125% = 75

So if 60 is 100%, then 75 is 25% more than 60.

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Solve for x. i'll give brainiest!
pogonyaev

Answer:

5

Step-by-step explanation:

x = 5

6 0
2 years ago
A test has 20 questions. The test awards 3 points if the answer is correct and takes away 1 point if the answer is incorrect. A
qaws [65]

Answer:

40

Step-by-step explanation:

15x3 = 45

45-5 =40

5 0
3 years ago
Let u,v,wu,v,w be three linearly independent vectors in R7R7. Determine a value of kk, k=k= , so that the set S={u−3v,v−2w,w−ku}
11Alexandr11 [23.1K]

Answer:

1/6

Step-by-step explanation:

For a set of vectors a, b and c to be linearly dependent, the linear combination of the set of vectors must be zero.

C1a + C2b + C3c = 0

From the question, we are given the set S={u−3v,v−2w,w−ku}, the corresponding vectors are a(0, -3, 1), b(-2,1,0) and c(1,0,-k)

The values in parenthesis are the ccoefficients of w, v and u respectively.

On writing this vector as a linear combination, we will have;

C1(0, -3, 1) + C2(-2,1,0) + C3(1,0,-k) = (0,0,0)

0-2C2+C3 = 0........ 1

-3C1+C2 = 0 ........... 2

C1-kC3 = 0 ….......... 3

From equation 2, 3C1 = C2

Substituting into 1, -2(3C1)+C3 = 0

-6C1+C3 = 0

-6C1 = -C3

6C1 = C3.…..4

Substitute 4 into 3 to have

C1-k(6C1) = 0

C1 = k6C1

6k = 1

k = 1/6

Hence the value of k for the set of vectors to be linearly dependent is 1/6

6 0
3 years ago
The difference of three times a number and 4 is 32. Find the number
Angelina_Jolie [31]

Answer:

3x - 4 = 32

Step-by-step explanation:

We solve for x to find the number (knowing that x is the unknown number).

3x - 4 = 32

3x = 32 + 4

3x = 36

x/3 = 36/3

x = 12

3 0
2 years ago
Can you convert 300 grams to ounces
GREYUIT [131]
1 gram = 0.035274 ounces

So 300 grams = 10.5822 ounces
4 0
3 years ago
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