Answer:
17.03052 g/mol
Explanation:
Ammonia formula is given as NH3.
To estimate the molar mass of any compound, we have to add up the molar masses of every atom of the given compound. Ammonia comprises of one nitrogen atom and three hydrogen atoms.
So the molar mass of ammonia is
N: 14.0067 g/mol
H: 1.00794 g/mol
The molar mass of ammonia will thus be
14.0067 g/mol +3× 1.00794 g/mol =17.03052 g/mol
Answer:
HCl acts as an excess reagent
Explanation:
The reaction equation is;
PbO + 2HCl → PbCl2 + H20
Number of moles of PbO = 13g/223.2 g/mol = 0.058 moles
Since the mole ratio is 1:1, 0.058 moles of PbCl2 is produced
Number of moles of HCl = 6.4 g/36.5g/mol = 0.175 moles
2 moles of HCl yields 1 mole of PbCl2
0.175 moles yields 0.175 moles * 1/2
= 0.0875 moles of PbCl2
Hence; PbO yields the least number of moles of product so it is the limiting reactant and HCl is the reactant in excess
Trail mix
Explanation:
Trail mix is a heterogeneous mixture due to its composition.
It is made up of nuts, raisins, seeds, berries, chocolate,
- Heterogeneous mixtures are mixtures whose constituents are existing in at least two different phases.
- There are different types of heterogeneous mixtures.
- Examples are muddy-water, aerated drinks, solid particles suspended in air.
learn more:
Heterogeneous mixtures brainly.com/question/1446244
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Answer:
The correct answer is 89.6 L
Explanation:
We have the following chemical equation and the molar masses for the reaction:
3H₂(g) + N₂ --> 2 NH₃
6 g 28 g 34 g
That means that 3 moles of H₂ (6 g) reacts with 1 mol of N₂ (28 g) and gives 2 moles of NH₃ (34 g). In order to calculate how many liters of NH₃ result from the reaction of 12 grams of H₂ and 28 grams of N₂, we have to first figure out which reactant is the <em>limiting reactant</em>. According to the equation, if 6 grams of H₂ reacts with 28 g of N₂, and we have 12 grams:
6 g H₂------- 28 g N₂
12 g H₂-------- X = 12 g H₂ x 28 g N₂/6 g H₂ = 56 g N₂
We need 56 g of N₂ but we have 28 g of N₂, so <em>N₂ is the limiting reactant</em>. With the limiting reactant we can calculate the moles of product (NH₃) we will obtain:
We have 28 g N₂ -----> 28 g/14 g/mol = 2 moles N₂
1 mol N₂ ----------- 2 moles NH₃
2 mol N₂ --------- X = 2 mol N₂ x 2 moles NH₃/1 mol N₂ = 4 mol NH₃
Finally, we convert the moles of NH₃ to liters:
1 mol gas at STP = 22.4 L
Liters NH₃ obtained = 4 moles NH₃ x 22.4 L/1 mol = 89.6 L
Carbon-14, 14C, or radiocarbon, is a radioactive isotope of carbon with a nucleus containing 6 protons and 8 neutrons.
You need to know that the atomic number of nitrogen is 7, and you subtract that from the mass number to get16-7= 9.