Answer:
Specific heat of metal = 0.26 j/g.°C
Explanation:
Given data:
Mass of sample = 80.0 g
Initial temperature = 55.5 °C
Final temperature = 81.75 °C
Amount of heat absorbed = 540 j
Specific heat of metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 81.75 °C - 55.5 °C
ΔT = 26.25 °C
540 j = 80 g × c × 26.25 °C
540 j = 2100 g.°C× c
540 j / 2100 g.°C = c
c = 0.26 j/g.°C
A is the correct answer from what i understand in this question
Answer:
The rate of reaction changes by a factor 6.
Explanation:
Given the reaction is first order.
Let us assume the initial concentration of 
is 
and the initial concentration of 
is 
.
So, we can write the rate of the reaction as
![R=k[A][B]](https://tex.z-dn.net/?f=R%3Dk%5BA%5D%5BB%5D)
Where,
is the rate of reaction. And 
is the rate constant.
Also, the initial concentration of has been increased by 
, and the initial concentration of was increased by factor 
.
So, we have
![R'=k[1.5A][4B]\\R'=6k[A][B]\\R'=6R](https://tex.z-dn.net/?f=R%27%3Dk%5B1.5A%5D%5B4B%5D%5C%5CR%27%3D6k%5BA%5D%5BB%5D%5C%5CR%27%3D6R)
We can see the rate of reaction changes by a factor 6.
Hey there,
<span>contact metamorphism
</span>
Hope this help :))
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The 2 represents that it is a double carbon bond
it looks like..
C-C = C-C
