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Hoochie [10]
2 years ago
9

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER what is the value o

f X in simplest radical form?
X=_____

Mathematics
2 answers:
dusya [7]2 years ago
8 0

Answer:

x = 29

Step-by-step explanation:

To find x, we can use the Pythagorean theorem.

a^2 + b^2 = c^2

21^2 + 20^2 = x^2

441 + 400 = x^2

841 = x^2

\sqrt{841} = \sqrt{x^2}

29 = x

ivanzaharov [21]2 years ago
5 0

Answer:

x= 29

Step-by-step explanation:

use Pythagoras because it has a right angle and 2 sides length is given.

when the hypoteneus(side opposite the right angle) is the value you are finding out you use the equation : x²+y²=hypoteneus² (Pythagoras)

then you sub in the values you are given

(21)² + (20)² = hypoteneus²

them take the square root (²) to the opposite side to find the hypoteneus

square root (441+400) = hypoteneus

now you can put into a calculator and you get the value

hypoteneus =29 (for reference to hypoteneus is the same as X-the value you are looking for)

therefore, x=29

for extra reference, say you want to work out a side that is not the hypotenues you use the formula ,

(side u looking for)² = (hypotenues)² - (other side given)²

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Step-by-step explanation:

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Jim is 5 years older than Cindy. 4 years ago, the sum of their ages was 21. Find each of their ages now.
Dmitry_Shevchenko [17]
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3 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
2 years ago
Nessa had $50 n her savings and it increased by 20%. How much money is in her account?
vredina [299]

Answer:

$60

Step-by-step explanation:

If it is increasing annually then next year the savings will be $50+20% of $50

=>$50+$10

=>$60

4 0
3 years ago
Read 2 more answers
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